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NISA [10]
3 years ago
14

Match these items.

Chemistry
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

Here's what I get  

Explanation:

There are two methods of naming esters.

(a) Common names

alkyl alcohol + carboxylic acid ⟶ alkyl carboxylate

To form the name of an ester, you drop the alcohol and -ic acid ending from the names of the reactants.

The name of the ester consists of two words: the name of the alcohol followed by the acid name with the ending -ate.

(b) IUPAC (systematic) names

alkanol + alkanoic acid ⟶ alkyl alkanoate

To form the name of an ester, you drop the -anol and -ic acid endings from the names of the reactants.

The name of the ester consists of two words with the corresponding endings -yl and -ate.

You don't mix the common and IUPAC systems in the same name.

1. ethanol + benzoic acid ⟶ ethyl benzoate

2. benzyl alcohol + acetic acid ⟶ benzyl acetate

3. butanol + butanoic acid ⟶ butyl butanoate (IUPAC)

   butyl alcohol + butyric acid ⟶ butyl butyrate (common)

4. pentanol + propanoic acid ⟶ pentyl propanoate (IUPAC)

    n-pentyl alcohol + propionic acid ⟶ n-pentyl propionate (common)

5. isopropyl alcohol + formic acid ⟶ isopropyl formate

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Calculate the molar mass for Cr2(SO3)3. Be sure to include units.<br><br> Number: <br><br> Units:
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Answer:

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table

Explanation:

<u>Step 1: Define</u>

Cr₂(SO₃)₃

<u>Step 2: Identify</u>

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3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

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