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vagabundo [1.1K]
4 years ago
12

Is every closed shape a polygon

Mathematics
2 answers:
kvv77 [185]4 years ago
7 0
Actually yea every closed shape a polygon.
Eddi Din [679]4 years ago
6 0
Every closed shape is a polygon because the definition of polygon is any closed shape.

Hope this helps... mark as Brainliest plz
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Find the measure for angle f<br><br> 46<br> 34<br> 122<br> 58
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Answer:

\angle f = 122\degree

Step-by-step explanation:

\angle d = 58\degree (vertical angles)

\angle f+\angle d= 180\degree

(Interior angles on the same side of transversal)

\angle f+ 58\degree = 180\degree

\angle f = 180\degree-58\degree

\huge \orange {\boxed {\angle f = 122\degree}}

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Step-by-step explanation:

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3 years ago
A man has 32 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 545 cents, how many d
inn [45]

A dime is worth 10 cents and a quarter is worth 25 cents.

Let D be the number of dimes and Q be the number of quarters.

Since the total amount of coins in the pocket is 32, then:

D+Q=32

On the other hand, the total value of D dimes is 10D, while the total value of Q dimes is 25Q. Then, the total value of D dimes and Q cuarters is 10D+25Q, which must be equal to 545. Then:

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Notice that we have found a 2x2 system of equations:

\begin{gathered} D+Q=32 \\ 10D+25Q=545 \end{gathered}

Solve the system using the substitution method. To do so, isolate D from the first equation and replace the expression for D into the second equation to obtain a single equation in terms of Q:

\begin{gathered} D+Q=32 \\ \Rightarrow D=32-Q \\  \\ 10D+25Q=545 \\ \Rightarrow10(32-Q)+25Q=545 \\ \Rightarrow320-10Q+25Q=545 \\ \Rightarrow25Q-10Q=545-320 \\ \Rightarrow15Q=225 \\ \Rightarrow Q=\frac{225}{15} \\  \\ \therefore Q=15 \end{gathered}

Replace back Q=15 into the expression for D to find the amount of dimes:

\begin{gathered} D=32-Q \\ =32-15 \\ =17 \end{gathered}

Therefore, the amount of dimes that the man has is 17.

7 0
1 year ago
Plz help due tomorrow if correct ill give brailiest
Annette [7]
C) the left side of the equation should be -15 + 3r after distributing.
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