Answer:
Assumption: the acceleration of this bus is constant while the brake was applied.
Acceleration of this bus: approximately
.
It took the bus approximately
to come to a stop.
Explanation:
Quantities:
- Displacement of the bus:
. - Initial velocity of the bus:
. - Final velocity of the bus:
because the bus has come to a stop. - Acceleration,
: unknown, but assumed to be a constant. - Time taken,
: unknown.
Consider the following SUVAT equation:
.
On the other hand, assume that the acceleration of this bus is indeed constant. Given the initial and final velocity, the time it took for the bus to stop would be inversely proportional to the acceleration of this bus. That is:
.
Therefore, replace the quantity
with the expression
in that SUVAT equation:
.
Simplify this equation:
.
Therefore,
.
In this question, the value of
,
, and
are already known:
Substitute these quantities into this equation to find the value of
:
.
(The value of acceleration
is less than zero because the velocity of the bus was getting smaller.)
Substitute
(alongside
and
) to estimate the time required for the bus to come to a stop:
.
Answer:
force acting on the parent = 25 N .
Explanation:
According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .
Answer is 25 N .
Answer:
2.55 m
Explanation:
Elastic energy = gravitational energy
½ kx² = mgh
h = kx² / (2mg)
h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)
h = 2.55 m
Answer:
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5.7 kilometers is equal to 3.5418157957528034 miles