Explanation:
Expression for energy balance is as follows.
or, 
Therefore,
Hence, expression for exit velocity will be as follows.
= ![V^{2}_{1} + 2C_{p}(T_{1} - T_{2})]^{0.5}](https://tex.z-dn.net/?f=V%5E%7B2%7D_%7B1%7D%20%2B%202C_%7Bp%7D%28T_%7B1%7D%20-%20T_%7B2%7D%29%5D%5E%7B0.5%7D)
As 
for the given conditions is 1.007 kJ/kg K. Now, putting the given values into the above formula as follows.
![V_{2} = V^{2}_{1} + 2C_{p}(T_{1} - T_{2})]^{0.5}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20V%5E%7B2%7D_%7B1%7D%20%2B%202C_%7Bp%7D%28T_%7B1%7D%20-%20T_%7B2%7D%29%5D%5E%7B0.5%7D)
= ![[(350 m/s)^{2} + 2(1.007 kJ/kg K) (30 - 90) K \frac{1000 m^{2}/s^{2}}{1 kJ/kg}]^{0.5}](https://tex.z-dn.net/?f=%5B%28350%20m%2Fs%29%5E%7B2%7D%20%2B%202%281.007%20kJ%2Fkg%20K%29%20%2830%20-%2090%29%20K%20%5Cfrac%7B1000%20m%5E%7B2%7D%2Fs%5E%7B2%7D%7D%7B1%20kJ%2Fkg%7D%5D%5E%7B0.5%7D)
= 40.7 m/s
Thus, we can conclude that velocity at the exit of a diffuser under given conditions is 40.7 m/s.
The first thing we must do for this case is the sum of forces in a horizontal direction.
We have then:
Substituting values we have:
From here, we clear the mass of the object:
We now look for the weight of the object.
Where,
g: acceleration of gravity (9.8 m/s^2)
Substituting values:
Answer:
the weight of the object is:
option 4
Answer:
"The capacity of a system to perform work of any type."
Explanation:
The best statement to describe Energy is:
"The capacity of a system to perform work of any type."
Proton
charge +
electron
charge -
neutron
charge neutral
