Which type of radiation has the highest penetrating power?

The model below shows a carbide ion. 8 light grey and 6 dark grey balls sit at the center with 2 concentric black rings around t

azamat

Answer:

This carbide ion change into a neutral carbon atom.

Explanation:

Given that,

Light grey balls = 8

dark grey balls = 6

medium grey balls = 2

Charge on dark grey ball = +1

Charge on light grey ball = 0

Charge on medium grey ball = -1

We need to change this carbide ion to a neutral carbon atom

Using given data

A dark grey ball has one positive charge. It means, it is a proton.

A light grey ball has has zero charge. It means, it is a neutron.

A medium grey ball has one negative charge.It means, it is a electron.

We know that,

The number of proton and number of electron is equal in a neutral atom.

So, No charge is present on the given model of atom.

Therefore, we can say that the atom is neutral.

We know that,

The sum of total number of protons presents in an atom it is called atomic number.

So, The total number of protons is 8, the total number of electrons is 8 and the total number of neutrons is 9 in given atom.

Hence, This carbide ion change into a neutral carbon atom.

6 0

4 years ago

A pool and stops at the

Bas_tet [7]

In Linear motion the swimmer swims

8 0

3 years ago

A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 23.0 m/s on a day when the speed of sound

kobusy [5.1K]

Doppler Effect is required to solve the problem. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. The general formula of observed frequency, due to Doppler's effect is as follows,

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0$ = Frequency observed by observer

v = Velocity of Sound

$v_0$ = Velocity of observer

$v_s$ = Velocity of source

$f_s$ = Frequency of source

PART A) Replacing our values we have that,

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0 = (\frac{344+0}{344-23})(412)$

$f_0 = 441.52Hz$

PART B) Here the same procedure is performed but this time repeated in the opposite direction.

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0 = (\frac{344+23}{344-0})(420)$

$f_0 = 448.08Hz$

4 0

3 years ago

Which is not part of nuclear chemistry? A. Strong nuclear force B. Double-replacement reactions C. Radioactivity D. Nuclear deca

ziro4ka [17]

The correct choice is

B. Double-replacement reactions

in this type of reaction , two ionic compounds react and swaps their cations or anions giving two new compounds in the product. hence the double replacement reactions does not deal with the nucleus. all other terms like strong nuclear forces, radioactivity and nuclear decay deal with the nucleus.

8 0

4 years ago

Read 2 more answers

Is water wet? I think it is but people think it isn’t

alexandr402 [8]

Water isn't wet. Wetness is a description of our experience of water; what happens to us when we come into contact with water in such a way that it impinges on our state of being. We or our possessions get wet

4 0

3 years ago

Read 2 more answers