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Talja [164]
3 years ago
7

A marble with a mass of 1.5 grams rolls at a constant rate at a constant rate of 0.50 cm/s across a table. What is the magnitude

of the marbles's momentum?
Physics
2 answers:
Leno4ka [110]3 years ago
3 0
Ok so momentum is the product of mass and velocity. Its SI unit is Kg m/s

The marble's velocity is 0.5 cm/s and it's mass is 1.5.

Multiply this -> 0.5 * 1.5 = 0.75 g cm/s

Usually everything in Physics is converted into SI units therefore the SI measurement of the marble is 0.00000075 Kg m/s


Llana [10]3 years ago
3 0

Answer:

Momentum, p=7.5\times 10^{-6}\ kg-m/s

Explanation:

It is given that,

Mass of the marble, m = 1.5 gm = 0.0015 kg

Speed of the marble, v = 0.5 cm/s = 0.005 m/s

We need to find the momentum of the marble. It can be given by the product of mass and velocity i.e.

p= m\times v

p= 0.0015\ kg\times 0.005\ m/s

p = 0.0000075 kg-m/s

p=7.5\times 10^{-6}\ kg-m/s

So, the marbles's momentum is 7.5\times 10^{-6}\ kg-m/s. Hence, this is the required solution.

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