Alike because they both act on the quarks making up the nucleons and they have very short ranges. The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei. Which also makes them very different
Complete Question
The complete question is shown on the first uploaded image
Answer:
a

b

Explanation:
From the question we are told that
The amplitude is 
The period is 
The test weight is 
Generally the radial acceleration is mathematically represented as

at maximum angular acceleration

So

Now
is the angular velocity which is mathematically represented as

Therefore
![a_{max} = [\frac{2 * \pi}{T} ]^2 * A](https://tex.z-dn.net/?f=a_%7Bmax%7D%20%3D%20%20%5B%5Cfrac%7B2%20%2A%20%20%5Cpi%7D%7BT%7D%20%5D%5E2%20%2A%20A)
substituting values
![a_{max} = [\frac{2 * 3.142}{17} ]^2 * 0.018](https://tex.z-dn.net/?f=a_%7Bmax%7D%20%3D%20%20%5B%5Cfrac%7B2%20%2A%20%203.142%7D%7B17%7D%20%5D%5E2%20%2A%200.018)

Generally this test weight is mathematically represented as
Where k is the spring constant
Therefore

substituting values


B. a solar storm that moves across the sun's surface
The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is
- The length variation is zero
- In the graph the line is horizontal so there is no change in length with temperature
Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written
ΔL = α L₀ ΔT
Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature
In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.
The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹
In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is
- The length variation is zero
- In the graph the line is horizontal so there is no change in length with temperature
Learn more here: brainly.com/question/18717902