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anyanavicka [17]
3 years ago
13

3. Some guitarists like the feel of a set of strings that all have the same tension. For such a guitar, the G string (196 Hz) ha

s a mass density of 0.31 g/m. What is the mass density of the A string (110 Hz)
Physics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

0.98 g/m

Explanation:

Note: Since Tension and frequency are constant,

Applying,

F₁²M₁ = F₂²M₂............... Equation 1

Where F₁ = Frequency of the G string, F₂ = Frequency of the A string, M₁ = mass density of the G string, M₂ = mass density of the A string.

make M₂ the subject of the equation

M₂ = F₁²M₁/F₂²............... Equation 2

From the question,

Given: F₁ = 196 Hz, M₁ = 0.31 g/m, F₂ = 110 Hz

Substitute these values into equation 2

M₂ = 196²(0.31)/110²

M₂ = 0.98 g/m

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Answer:

work done is -2.8  × 10⁻⁶ J

Explanation:

Given the data in the question;

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In case2, mass is pulled aside a small distance of 8 cm and released from rest. so let θ₁ be the angle made by mass with vertical axis.

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Now, the required work done will be;

W = \int\limits^{\theta_2} _{\theta_1} {r} \, d\theta

W = \int\limits^{\theta_2} _{\theta_1} {-mgl sin\theta } \, d\theta

W = -mgl  \int\limits^{0.047 } _{0.045 } {sin\theta } \, d\theta

W = -mgl[ -cosθ ]^{0.047}_{0.045 }

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W = 6 × 9.8 × 1.7 × [ -2.8 × 10⁻⁸ ]

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3 years ago
A 34.1-mL sample of benzene at 20.8°C was cooled to its melting point, 5.5 °C, and then frozen at 5.5 °C. Calculate the quantity
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Answer:

4541.8 J

Explanation:

First we find the mass of benzene available

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Then we find the amount of heat transferred by two processes:

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3 0
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Answer:

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