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Ksenya-84 [330]
2 years ago
7

Solve 3(x - 5) = 2(x + 5)

Mathematics
1 answer:
stepladder [879]2 years ago
3 0

Answer:

it should be x=25

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Please help with this!!! 25 points and i'll mark you brainliest!!! Show how you got answer!!!
HACTEHA [7]

Answer:

17.9°

Step-by-step explanation:

From trigonometry:

Opposite = 14

Adjacent = x

theta = 38°

hence;

tan theta = opposite/ adjacent

tan38° = 14/x

x = 14/tan38°

x = 17.9°

6 0
2 years ago
A quadrilateral has vertices (2, 0), (0, –2), (–2, 4), and (–4, 2). Which special quadrilateral is formed by connecting the midp
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The first step to take is to plot the coordinates of the figure. Next, we caculate the distances of the sides of the polygon using distance formula given the coordinates of points. Next we get the midpoint of each side and connect them to each other. we calculate again the distances. The resulting figure is composed of four congruent sides but the angles are not perpendicular. The answer is D. rhombus
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2 years ago
Use the image below to answer the following question.
Rainbow [258]

Answer:9

Step-by-step explanation:pp

3 0
3 years ago
What number is 54% of 125 type an integer or a decimal round to the nearest tenth
eimsori [14]
Answer is 67.5

To get this you must first turn 54% into a decimal.
54%---> .54
125*.54= 67.5
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4 0
3 years ago
Read 2 more answers
What is the relationship between exponentials and logarithms? How can you use these to solve equations? Provide an example in yo
Sveta_85 [38]

Answer:

Exponentials and logarithms are inverses of each other.

Step-by-step explanation:

Exponentials and logarithms are inverses of each other.

For logarithmic function:

Domain = \left ( 0,\infty  \right ), Range = \left ( -\infty ,\infty  \right )

Vertical asymptote is y - axis.

x - intercept is (1,0)

For exponential function:

Domain = \left ( -\infty ,\infty  \right ), Range = \left ( 0,\infty  \right )

Horizontal asymptote is x - axis.

y- intercept is (0,1)

Both exponential and logarithmic functions are increasing.

For example:

Solve: \log x=\frac{\log 5+\log 3}{\log 3^2}

\log x=\frac{\log 5+\log 3}{\log 3^2}\\\log x=\frac{\log (5\times 3)}{2\log 3}\,\,\left \{ \because \log (ab)=\log a+\log b\,,\,\log a^b=b\log a \right \}\\=\frac{\log 15}{2\log 3}

\Rightarrow \log x=\frac{\log 15}{2\log 3}\\\Rightarrow x=e^{\frac{\log 15}{2\log 3}}\,\,\left \{ \because \log x=y\Rightarrow x=e^y \right \}

4 0
3 years ago
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