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Strike441 [17]
3 years ago
10

A car going around a curve with a radius of 15m experiences a centripetal acceleration of 2.5 m/s2. How fast is the car going?

Physics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

Explanation:

The formula for centripetal acceleration is

a_c=\frac{v^2}{r} . Filling in:

2.5=\frac{v^2}{15} and

v=\sqrt{2.5(15)} so

v = 6.1 m/s

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A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet
marin [14]

Answer:

option A is correct

Explanation:

Given:

The length to be painted = m miles

The width to be painted = t inches

Area painted in 1 gallon = p square feet

Converting the every given dimension in feet, we have

length to be painted = m × 5280 feet

width to be painted = t/12 feet

area to be painted = (m × 5280 feet) × t/12 feet

now, applying the unitary method, we have

p square feet is painted ⇒ 1 gallon

1 square feet is painted ⇒ 1/p gallon

(m × 5280 feet) × t/12 feet  square feet is painted ⇒ [(m × 5280 feet) × t/12 feet ] × 1/p gallon

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3 0
4 years ago
Two people are carrying a uniform wooden board that is 3.00 m long and weighs 160 N. If one person applies an upward force equal
Amanda [17]

Answer:

0.9 meters

Solution:

In these type of questions there are two equations:

First one is Force Balance and second one is Torque Balance.

<u>Force Balance</u>

First equation is generally used to know the magnitude of the force applied.

Since they have to lift wooden board in order to carry it, therefore they have to apply a counter force to overcome its weight, which is 160 N.

So the net force applied by the two men in upward direction is 160 N.

The force applied by person 1 (as in the figure attached) is 60 N and by person 2 is F N. So,

60 + F = 160

∴ F = 100 N

<u>Torque Balance</u>

(<em>Torque is nothing but a twisting force that tends to cause rotation.</em>

<em>To calculate torque multiply the force applied with the perpendicular distance between axis of rotation and line of application of force</em>)

The second equation is generally used to know the position of the force applied.

Since they are carrying wooden board in horizontal position, therefore there is no net torque on the wooden board.

To calculate torque first of all choose the axis of rotation. Here, there is no rotation so you can choose any axis of rotation which can help you to calculate the distance of application of force. Here the axis of rotation is chosen as the axis perpendicular to the wooden board passing through the center of it.

Since torque of two person are opposing each other as one is in clockwise direction and other one is in anticlockwise direction, therefore, if they are equal then the net torque will become zero. So,

60 \times 1.5 = F \times x

60 \times 1.5 = 100 \times x

90 = 100 \times x

x = \frac{90}{100}

x = 0.9 meters

<em>( NOTE: If you apply force in the same half side then the torque won't oppose each other rather it will support each other)</em>

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Which procedure would cause charged particles in a conductor to move in the same direction?
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