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Valentin [98]
4 years ago
12

Write the steps used for making tea by using the words: solution, solvent,solute,dissolve,soluble, insoluble, filtrate and resid

ue.
answer​
Chemistry
1 answer:
katen-ka-za [31]4 years ago
6 0

Answer:

Water is solvent and milk, tea powder and sugar is solute.

Explanation:

First take a specific mount of water in teapot which is a solvent and heat it for several minutes. After boiling of water, add 1 to 2 table spoon tea powder in water which is a solute and allow it for boiling. After that add milk and sugar according to your preference and tea is made which is a solution. The milk and sugar dissolve in the water but the tea powder did not dissolve so it can be filtrate with the help of filtration tool and all the residue trap at that tool while the tea is clean from all undissolved particles.

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Compare the solubility of silver iodide in each of the following aqueous solutions:
Semenov [28]

Answer:

Compare the solubility of silver iodide in each of the following aqueous solutions:

a. 0.10 M AgCH3COO

b. 0.10 M NaI

c. 0.10 M KCH3COO

d. 0.10 M NH4NO3

1. More soluble than in pure water.

2. Similar solubility as in pure water.

3. Less soluble than in pure water.

Explanation:

This can be explained based on common ion effect.

According to common ion effect the solubility of a sparingly soluble salt decreases further in a solution which has a common ion to it.

The solubility of AgI(s) silver iodide in water is shown below:

AgI(s)  Ag^{+}(aq)+I^{-}(aq)\\

a. a. 0.10 M AgCH3COO has a common ion Ag+ with AgI.

So, AgI is less soluble than in pure water in this solution.

b. 0.10 M NaI has a common ion I- with AgI.

So, AgI is less soluble than in pure water in this solution.

c. 0.10 M KCH3COO:

This solution has no common ion with AgI.

So, AgI has similar solubility as in pure water.

d. 0.10 M NH4NO3:

In this solution, AgI can be more soluble than in pure water.

7 0
3 years ago
Based on bond type, which compound has the
lorasvet [3.4K]
Based on bond type, CaCI2 has the highest melting point.
3 0
4 years ago
This solution contains equal concentrations of both hf(aq) and naf(aq). write the proton transfer equilibrium (net ionic) reacti
Viktor [21]
Net ionic reaction for the solution containing equal concentrations of both HF(aq) and NaF(aq) is as follow:
F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)
3 0
3 years ago
Read 2 more answers
What the difference between chlorine and non chlorine bleach?
padilas [110]
The basic difference between chlorine and blench is that a natural element, while bleach is a solution of many elements.

Hope this help..
5 0
3 years ago
Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce
Andru [333]

Answer:

The empirical formula is C4H8O

Explanation:

Step 1: Data given

Valproic acid is composed of C, H, and O

Mass of the sample = 0.165 grams

Mass of water = 0.166 grams

Mass of CO2 = 0.403 grams

Molar mass of water ( H2O) = 18.02 g/mol

Molar mass of CO2 = 44.01 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of O = 16.0 g/mol

Atomic mass H = 1.01 g/mol (H2 = 2.02 g/mol)

Step 2: The equation

CxHyOz + O2 → CO2 + H2O

Step 3: Calculate the number of carbon in the sample

The carbon comes from CO2

Mass C = (12.01 g/mol/44.01 g/mol) * 0.403 grams

Mass C = 0.110 grams

Step 4: Calculate mass of hydrogen in the sample

The hydrogen comes from H2O

Mass H = (2.02/18.02) * 0.166 grams

MAss H = 0.0186 grams

Step 5: Calculate mass of O

The mass of O in the sample = Mass of sample - mass of H - mass of C

The mass of O = 0.165 grams - 0.110 grams - 0.0186 grams

The mass of O = 0.0364 grams

Step 6: Calculate moles

Moles C = 0.110 grams / 12.01 g/mol = 0.00916 moles

Moles H = 0.0186 / 1.01 = 0.0184 moles

Moles O = 0.0364/16.0 = 0.00228 moles

Step 7: Calculate empirical formula

We divide by the smallest amount of moles

C: 0.00916/ 0.00228 = 4

H: 0.0184/0.00228 = 8

O: 0.00228/0.00228 = 1

The empirical formula is C4H8O

7 0
3 years ago
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