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Gnesinka [82]
3 years ago
9

Hydrogen sulfide gas H2S and aqueous iron(II) chloride are formed by the reaction of aqueous hydrochloric acid HCl and solid iro

n(II) sulfide . Write a balanced chemical equation for this reaction
Chemistry
2 answers:
jasenka [17]3 years ago
5 0

Answer:

The balanced chemical equation for this reaction is:

2HCl (aq) + FeS (s) -----> FeCl2 (aq) + H2S (g)

Explanation:

Sav [38]3 years ago
5 0

Answer:

2HCl(aq.)+FeS(s)\rightarrow H_{2}S(g)+FeCl_{2}(aq.)

Explanation:

Unbalanced equation: HCl(aq.)+FeS(s)\rightarrow H_{2}S(g)+FeCl_{2}(aq.)

Balance Cl: 2HCl(aq.)+FeS(s)\rightarrow H_{2}S(g)+FeCl_{2}(aq.)

We can see both side of equation contains two H atoms, two Cl atoms, one Fe atom and one S atom.

Therefore it is a balanced equation.

Balanced equation: 2HCl(aq.)+FeS(s)\rightarrow H_{2}S(g)+FeCl_{2}(aq.)

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What is the largest area of a circle that can be made from a piece of thread 25.2cm long assume no knot
Zarrin [17]

Answer:

50.2 cm^2

Explanation:

Here we want to find the largest area of a circle that can be made from a piece of thread 25.2 cm long, assume no knot .

This means that the circumference of the circle must equal to the length of the thread, so we can write:

L = 25.2 cm

And the circumference can be written as:

2\pi r = L = 25.2

where

r is the radius of the circle

Solving for r, we find the radius:

r=\frac{L}{2\pi}=\frac{25.2}{2\pi}=4.0 cm

The area of a circle is given by the formula

A=\pi r^2

So in this case, we find:

A=\pi (4.0)^2=50.2 cm^2

7 0
4 years ago
Why does a solid have an definite shape?
Leno4ka [110]
Because the particle in the solid shape is pack and closely .
4 0
4 years ago
When a buffalo egg and sperm unite, a fertilized egg with 60 chromosomes is produced. How many chromosomes do the egg and sperm
Basile [38]
Your answer would be A
hope this helps :3
8 0
3 years ago
The chemical equation shows only the reactants and one product. How many H atoms must be present in the second product that is f
cestrela7 [59]

Answer: In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. If we count the number of hydrogen atoms in the reactants and products, we find two hydrogen atoms.

4 0
3 years ago
The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
Vinil7 [7]

Answer:

Here's what I get  

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}

3. Check:

Compare the final concentration with the original

\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}

7 0
3 years ago
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