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Fudgin [204]
3 years ago
5

A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is t

he volume of the balloon at 46°C
Chemistry
1 answer:
rosijanka [135]3 years ago
7 0
Due to the ideal gas law, we have an equation: PV=nRT. So when the pressure and amount of gas are constant, V1/T1=V2/T2. Temperature using the unit of K. So the answer is 535*319/296=576.6 mL.
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What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
x:=5.8* 16/84 
this is approximately 1.1
4 0
2 years ago
What thype of bond requires the give and take of electrons ?
DedPeter [7]
Ionic bond involves electrostatic attraction between oppositely charged ions.
The ions are atoms that have gained 1 or more electrons and atoms that have lost 1 or more electrons.
<span>Answer: The type of bond that requires the give and take of electrons is Ionic bond</span>
6 0
3 years ago
Read 2 more answers
How many grams of iron can be made with 21.5g of Fe2O3
SIZIF [17.4K]

The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g

We'll begin by writing the balanced equation for the reaction. This is given below:

2Fe₂O₃ -> 4Fe + 3O₂

  • Molar mass of Fe₂O₃ = 159.7 g/mol
  • Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
  • Molar mass of Fe = 55.85 g/mol
  • Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

<h3>How to determine the mass of iron, Fe produced</h3>

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

Therefore,

21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe

Thus, 15.04 g of Fe were produced.

Learn more about stoichiometry:

brainly.com/question/9526265

#SPJ1

5 0
1 year ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
2 years ago
Calculate the amount of solute needed for 1000 ml of 15% sodium thiosulfate
maksim [4K]
15% =  15 grams of solute in 100 mL solution

15 g --------------- 100 mL
?? ------------------ 1000 mL

1000 x 15 / 100 = 

15000 / 100 => 150 g of solute

hope this helps!
7 0
3 years ago
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