The atom will lose three valence electrons.
<h3>What is meant by valence electron ?</h3>
- A valence electron is an electron that is part of an atom's outer shell in chemistry and physics. If the outer shell is open, the valence electron can take part in the creation of a chemical bond.
- Each atom in the bond contributes one valence electron to create a shared pair in a single covalent bond.
- The chemical properties of an element, such as its valence—whether it can bond with other elements and, if so, how readily and with how many—can be affected by the presence of valence electrons. In this way, the electronic configuration of an element greatly influences its reactivity.
- A valence electron for a main-group element can only be found in the outermost electron shell; for a transition metal, it can also be found in an inner shell.
Learn more about valence electron refer to :
brainly.com/question/371590
#SPJ4
To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:
Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate
Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:
Mass of Fe = 220 mg ferrous sulfate ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg
atomic number is equal to proton number
so the proton number will be 87
Answer:
n = 0.3 mol
Explanation:
Given data:
Volume of gas = 8.0 L
Temperature of gas = 45 °C (45+273 = 318 K)
Pressure of gas = 0.966 atm
Moles of gas present = ?
Ideal gas constant = R = 0.021 atm.L/mol.K
Solution:
Formula:
PV = nRT
P = Pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Now we will put the values:
0.966 atm × 8 L = n × 0.0821 atm.L/mol.K × 318 K
7.728 atm.L = n × 26.12 atm.L/mol
7.728 atm.L / 26.12 atm.L/mol = n
n = 0.3 mol
Answer:
Explanation:
A) In H2SO4, the oxidation number of H is , that of S is , and that of O is .
In H₂SO₄ the oxidation sate of H is +1 (H₂= +2) that of sulfur is +6 and O is -2 (O₄= -8)
In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why two hydrogen atoms are attached with one SO₄ to balance the charge.
B) In CaSO4, the oxidation number of Ca is , that of S is . , and that of O is .
In CaSO₄ the oxidation sate of Ca is +2 that of sulfur is +6 and O is -2 (O₄= -8)
In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why one calcium atoms is attached with one SO₄ to balance the charge.
C) In HF, the oxidation number of H is , and that of F is .
In HF the oxidation state of hydrogen is +1 and that of fluorine is -1. Both form ionic compound.
