Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
Answer:
An equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Step-by-step explanation:
The given expression is:
x2-16x+12
Break the constant term:
x^2-16x-36 +48=0
[x^2-16x-36] +48=0
Now break the middle term inside the brackets
(x^2-18x+2x-36)+48=0
Take the common
[x(x-18) +2(x-18)]+48=0
(x-18)(x+2)+48=0
Thus an equation which has the same solution as the given equation is:
( x - 18 ) ( x + 2 ) + 48 = 0 ....
Since everything is half off, you save half of your money or %50.
The function ...
... g = |x| + 1
will map any integer x into the set of positive integers g.
