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Katena32 [7]
3 years ago
6

Match each term to its description. Match Term Definition Excess reactant A) Amount of product predicted to be produced by the g

iven reactants Limiting reactant B) Reactant that can produce more of the product Theoretical yield C) Reactant that can produce a lesser amount of the product
Chemistry
2 answers:
tia_tia [17]3 years ago
7 0

Answer:

Excess reactant - Reactant that can produce more of the product

Limiting reactant - Reactant that can produce a lesser amount of the product

Theoretical yield - Amount of product predicted to be produced by the given reactants

Explanation:

In every chemical reaction, there is a limiting reactant and there is an excess reactant.

The limiting reactant determines the amount of product obtained. It is the reactant that produces a lesser amount of the product.

The excess reactant is known to be the reactant that produces a greater amount of the product.

The theoretical yield is calculated using the limiting reactant and is the amount of product predicted to be produced by the given reactants.

-Dominant- [34]3 years ago
5 0

Answer:

Excess reactant - Reactant that can produce more of the product

Limiting reactant - Reactant that can produce a lesser amount of the product

Theoretical yield - Amount of product predicted to be produced by the given reactants

Explanation:

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If the methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume w
Sunny_sXe [5.5K]

116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C that was extracted and placed under STP conditions.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

The solubility of methane in water at 25 degrees Celcius is 1.3 x 10^{ -3} M. It implies   1.3 x 10^{ -3} moles of methane are dissolved in one litre of water.

The number of moles of methane in 4 L of water can be calculated as follows:

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Moles of methane = 5.2 x 10^{ -3}

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An ideal gas is an imaginary gas comprising of a large number of randomly moving particles and the motion between such articles is considered to be perfectly elastic. The ideal gas equation describes the relationship between pressure, volume, temperature and number of moles of a gas.

The expression for ideal gas equation is as follows:

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1 atm

V= ?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=273K

n=?

Putting value in the given equation:

\frac{PV}{RT}=n

5.2 x 10^{ -3} = \frac{1 \;atm\; X \;V}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 273}

V= 116.6 x 10^{ -3}

Hence, 116.6 x 10^{ -3} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions.

Learn more about the ideal gas here:

brainly.com/question/27691721

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