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nignag [31]
3 years ago
9

PLEASE HELP - TIMED!!!

Chemistry
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

B

Explanation:

Relative humidity can be found by subtracting dry bulb reading minus wet bulb reading. The greater the difference, the lower the relative humidity. B as the greates difference, therefore it indicates lower relative humidity.

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Pharmacists sometimes measure medicines in the unit of "grains," where 1 gr = 65 mg. The label on a bottle of aspirin reads "Asp
viva [34]

Answer:

325mg of Aspririn

Explanation:

First you should note the information that the problem gives you:

- The bottle of Aspirin has 5gr (grains)

- 1gr(grain) = 65mg (miligrams)

Also, the problem is asking about how many aspirin are in 5 gr (grains), so you should use a conversion factor, as follows:

-First you should put the quantity you need to convert:

5grAspirin

-Then you write the denominator of the conversion factor that must have the same units that you want to convert, in this case gr:

5grAspirin*\frac{}{1grAspirin}

-Then you write the numerator with the units that you want to obtain and the numerical equivalence between the units, in this case:

5grAspirin*\frac{65mgAspririn}{1grAspirin}

-Finally you multiply numerators and divide by denominators:

5grAspirin*\frac{65mgAspririn}{1grAspirin}=325mgAspririn

8 0
3 years ago
Which possible discovery would be attributed to an inorganic molecule?
egoroff_w [7]

Answer:

fireproofing spray used in firefighting can be termed as one of the possible discovery that would be attributed to an inorganic molecule.

Explanation: • There a number of advancement been made each day to improve the different process either domestic, industrial, or related to research work. As a number of professionals are always in search to get the right set of information or data to get to a more proper conclusion.

4 0
2 years ago
Read 2 more answers
For the reaction: 2 A (g) + B (s)= 2 C(s) + D (g)
jolli1 [7]

Answer:

The value of the equilibrium constant = 5.213

Explanation:

Here K_p (equilibrium constant) is referred to as the  partial pressure of product divided by the  partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation .

As such only gas appear in K_p  expression as solids takes a value of 1;

SO ; in the  given equation from the question:

2 A (g) + B (s) ----> 2 C(s) + D (g)

K_p = \dfrac{[D]}{[A]^2}

K_p = \dfrac{2.71}{0.721^2}

K_p = 5.213

The value of the equilibrium constant = 5.213

8 0
2 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
3 years ago
A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent
rusak2 [61]

Answer:

\boxed{4.7\times 10^{-9}}

Explanation:

Data:

MM = 848.952 g/mol  

   c = 4.0 x 10⁻⁶ g/L

  V = 1 L

Calculations:

(a) Mass of growth hormone

\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}

(b) Moles of growth hormone

\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}

8 0
3 years ago
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