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3 years ago

What combines to form compounds? A. atoms of elements B. molecules C. minerals D. valences

1 answer:

6 0

Arguably A, B and C are all correct. Atoms of elements can form compounds such as NaCl(table salt). Molecules form molecular compounds and minerals are just complex molecule compounds.

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Calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3

taurus [48]

1 $cm ^{3}$ = 0.001 $dm ^{3}$ . Therefore 200 $cm ^{3}$ = 0.2 $dm ^{3}$ . Molarity = $\frac{number of moles of NaCl}{volume of the solution} = \frac{0.1}{0.2} = 0.5 mol/dm^{3}$ . Hope this helps.

8 0

3 years ago

What's wrong with this thermochemical equation?

mafiozo [28]

This thermochemical equation needs to be balanced. Hence, option B is correct.

<h3>What is a balanced chemical equation?</h3>

A balanced equation contains the same number of each type of atom on both the left and right sides of the reaction arrow.

The balanced thermochemical equation is:

$H_2(g) + 2NaCl (s) + 3O_2 (g)$ → $2HCl (l) + 2Na (s) + 2O_3 (g)$

Hence, option B is correct.

Learn more about the balanced chemical equation here:

brainly.com/question/8062886

#SPJ1

7 0

1 year ago

Which best describes the tyndall effect? the scattering of light by solutes in a mixture the scattering of light by solvent in a

Oksanka [162]

the scattering of light by particles in a mixture

3 0

3 years ago

Read 2 more answers

Which of the following best describes an electron?

GenaCL600 [577]

B. It has a negative charge and much less mass than a proton.

3 0

2 years ago

Read 2 more answers

72.0 grams of water how many miles of sodium with react with it?

Flura [38]

Answer:

$\large \boxed{\text{8.00 mol}}$

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ: 18.02

2Na + H₂O ⟶ 2NaOH + H₂

m/g: 72.0

2. Moles of H₂O

$\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g H$_{2}$O}} = \text{3.996 mol H$_{2}$O}$

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

$\text{Moles of Na} = \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}$

7 0

3 years ago