Answer:
In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as
c=4.18Jg∘C
Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.
Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.
In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.
What if you wanted to increase the temperature of 1 g of water by 2∘C ?
This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.
And there you have it. The equation that describes all this will thus be
q=m⋅c⋅ΔT , where
q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature
In your case, you will have
q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C
q=10,450 J
Explanation:
If you have chipped or broken glassware then it is very important that you should take precaution yourself by conveying about it to your teacher and class mates.
By doing so you are making everybody aware to be cautious of the chipped or broken glassware.
Also, it is advised that you should dispose of it in the designated glass waste area.
Therefore, we can conclude that all actions that you should take if you have chipped or broken glassware as as follows.
- Dispose of it in the designated glass waste area.
Answer:
Answer B) 4.2x10^17
Explanation:
To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:
____________________________
Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30
Finally, the new equilibrium constant K3 is the product of the previous constants:
K3=K1'*K2=4.2x10^17
Answer:
Concentration of the sugar in the solution increases
