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3 years ago

What is the value of x in the following equation? 11^4x+1= 11^3x-7

Mathematics

2 answers:

Misha Larkins [42]3 years ago

4 0

Answer:

-8

Step-by-step explanation:

well since the equation has the same base of 11, you can just solve for x as you normally would. so the question becomes:

4x+1 = 3x -7

subtract one from both sides

4x = 3x - 8

subtract 3x from both sides

x = - 8

prohojiy [21]3 years ago

4 0

Answer:

x= -8

Step-by-step explanation:

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Can you please help me?

iren2701 [21]

Answer:

1 = 3

2 = 6

3 = 9

Step-by-step explanation:

for every # it is multiplied by 3 (ex. 7 • 3 = 21, 8 • 3 = 24, ect.)

therefore if it is multiplied by 3 each time

then 1 • 3 = 3

2 • 3 = 6

and 3 • 3 = 9

hope this helps :)

5 0

3 years ago

Read 2 more answers

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago

Determine if the two figures are congruent and explain your answer.

forsale [732]

The two figures are congruent because the side lengths are the same, therefore making the angle measures the same.

3 0

3 years ago

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Instructions:Drag each tile to the correct box. The radii of the planets in the solar system are given. Arrange the planets in i

pashok25 [27]

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Mars: 3.39 × 103 kilometers
Venus: 6.05 × 103 kilometers
Earth: 6.37 × 103 kilometers
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Uranus: 2.54 × 104 kilometers
Saturn: 5.82 × 104 kilometers
Jupiter: 6.99 × 104 kilometers

3 0

3 years ago

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Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Stella [2.4K]

Given:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

Measure of major ∠AOB:

The measure of major angle AOB can be determined by subtracting 360° and 30°