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3 years ago

Simply the expression below

Mathematics

2 answers:

Inessa [10]3 years ago

4 0

Answer:

Step-by-step explanation:

Ira Lisetskai [31]3 years ago

4 0

Answer:

D. (w-3)/(w-7)

Step-by-step explanation:

(w+3)(w-3)/(w-7)(w+3)

Hence, removing (w+3),

(w-3)/(w-7)

<em>Feel free to mark this as brainliest :D</em>

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

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3 years ago

The two linear functions f(x) and g(x) are shown below.<br> Which of the following is true

Vlada [557]

Answer:

Step-by-step explanation:

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3 years ago

Darius had 1/2 an inch of hair cut off. Anna had 3/4 an inch of hair cut off. Penelope had 5/8 an inch of hair cut off. Who had

Anestetic [448]

I don’t know I just need points

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2 years ago

Read 2 more answers

Please help me ASAP!!!

RoseWind [281]

Answer:

Step-by-step explanation:

0 is closed 8 is open

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3 years ago

Reflect quadrilateral CJKM across the y-axis. Find the location of K'.

Montano1993 [528]

$K(1,4)\rightarrow K^{\prime}(-1,4)$

Explanation

Step 1

find the coordinate of every point of the quadrilateral

C(-3,1)

J(0,1)

K(1,4)

M(4,-2)

Step 2

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

$(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)$

therefore

$\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}$

so, the answer is

$K^{\prime}(-1,4)$

i hope this helps you

4 0

1 year ago