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jarptica [38.1K]
3 years ago
5

Please help me I will give you the brain thing and extra points.

Chemistry
2 answers:
snow_tiger [21]3 years ago
7 0

Answer:

unbalanced

Explanation:

because two dogs are pulling it so it's not going to be in place?

ruslelena [56]3 years ago
4 0
Balanced is the answer
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A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What is the new v
guapka [62]

Ans: Final volume = 25.0 ml

<u>Given:</u>

Initial volume V1 = 50.0 ml

Initial pressure P1 = 20.0 atm

Final pressure P2 = 40.0 atm

<u>To determine:</u>

The final volume V2

<u>Explanation:</u>

Ideal gas equation: PV = nRT

under constant temperature, T and number of moles n we have:

PV = constant

or, P1V1 = P2V2

V2 = P1V1/P2 = 20*50/40 = 25 ml.

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3 years ago
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3 years ago
In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid sodium nitrate must be use
GarryVolchara [31]

The grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

According to the definition of molar concentration of a substance dissolved in a solution is defined as the ratio of the number of moles to the volume of the solution.

C = n/V

The number of moles is equal to the given mass divided by the molar mass.

n = m/Mm = n ×m

Given,

The volume of the solution of copper oxide = 0.53

Molar mass of copper oxide = 79.5

Concentration of copper oxide = 0.125

CuO = cVM

= 0.125 × 0.53 × 79.5

= 5.26g

Thus, we concluded that the grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

DISCLAIMER: The above question is wrong. The correct question is

Question: In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid copper oxide must be used to prepare a solution of this concentration?

learn more about molar concentration :

brainly.com/question/14803618

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2 years ago
What is the poh of a 4.5x10^-3 m oh- solution?
Ksju [112]
The formula for pOH is -log(M)

So, all we need to do is plug in that number! -log(4.5x10^-3)
That gives us 2.3, so the pOH is 2.3 :)
6 0
3 years ago
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What is the total pressure exerted by the mixture of gases only products or products + reactants?
dedylja [7]
Total = <span>products + reactants</span>
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