Ans: Final volume = 25.0 ml
<u>Given:</u>
Initial volume V1 = 50.0 ml
Initial pressure P1 = 20.0 atm
Final pressure P2 = 40.0 atm
<u>To determine:</u>
The final volume V2
<u>Explanation:</u>
Ideal gas equation: PV = nRT
under constant temperature, T and number of moles n we have:
PV = constant
or, P1V1 = P2V2
V2 = P1V1/P2 = 20*50/40 = 25 ml.
D. Changes
Hope this helps :)
The grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.
According to the definition of molar concentration of a substance dissolved in a solution is defined as the ratio of the number of moles to the volume of the solution.
C = n/V
The number of moles is equal to the given mass divided by the molar mass.
n = m/Mm = n ×m
Given,
The volume of the solution of copper oxide = 0.53
Molar mass of copper oxide = 79.5
Concentration of copper oxide = 0.125
CuO = cVM
= 0.125 × 0.53 × 79.5
= 5.26g
Thus, we concluded that the grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.
DISCLAIMER: The above question is wrong. The correct question is
Question: In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid copper oxide must be used to prepare a solution of this concentration?
learn more about molar concentration :
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The formula for pOH is -log(M)
So, all we need to do is plug in that number! -log(4.5x10^-3)
That gives us 2.3, so the pOH is 2.3 :)
Total = <span>products + reactants</span>
