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jarptica [38.1K]
3 years ago
5

Please help me I will give you the brain thing and extra points.

Chemistry
2 answers:
snow_tiger [21]3 years ago
7 0

Answer:

unbalanced

Explanation:

because two dogs are pulling it so it's not going to be in place?

ruslelena [56]3 years ago
4 0
Balanced is the answer
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The observed rotation of 2.0 gg of a compound in 50 mLmL of solution in a polarimeter tube 25-cmcm long is +47.2 ∘∘ . What is th
Anastaziya [24]

Answer:

[∝] = +472

Explanation:

Specific rotation in a solution is defined as:

[∝] = ∝ / c×l

Where:

[∝] is specific rotation, ∝ is observed rotation (In degrees), c is concentration in g/mL and l is path length (In dm).

∝: +47.2°

c: 2.0g / 50mL = 0.04g/mL

l: 25cm × (1dm /10cm) = 2.5dm

Replacing:

[∝] = +47.2° / 0.04g/mL×2.5dm = <em>+472</em>

I hope it helps!

4 0
3 years ago
Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(
Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

2KI(aq)+Cl_2(&#10;g)\rightarrow 2KCl(aq)+I_2

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by:\frac{1}{22.4 L}\times 8.5=0.3794 moles

0.3794 moles of Iodine gas are produced.

5 0
3 years ago
Read 2 more answers
Identify one way Ultra Violet Rays can be harmful to humans? Thank you so much!
valina [46]

Answer

It can Blind humans

Explanation:

6 0
3 years ago
25 grams of radon-222 remains after 15.28 days. How much radon was in the original sample? Write an equation for the decay of ra
Crazy boy [7]

Answer:

half-life = 3.8 days

total time of decay = 15.2 days

initial amount = 100. g

number of half-lives past: 15.2/3.8 = 4 half-lives

4 half-lives = 1/16 remains

100. g x 1/16 = 6.25 g

8 0
3 years ago
The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80
ZanzabumX [31]
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

             A(t) = A(o) (1/2)^(t/d)

where t is the certain period of time. Substituting the known values,

             A(t) = (20 mg)(1/2)^(85.80/14.30)

Solving,

           A(t) = 0.3125 mg

Hence, the answer is 0.3125 mg. 
7 0
3 years ago
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