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3 years ago

10

Dissolving salt in water reduces the intermolecular forces between water molecules. What most likely happens to the surface tens

ion of water when salt is dissolved in it?

2 answers:

Svetllana [295]3 years ago

7 0

If we dissolve salt in water they will reduce the intermolecular forces between water molecule and this will decrease the surface tension.

Surface tension is due to cohesive forces (the forces between molecules of same substance) hence as cohesive forces decreases the surface tension also decreases

Nuetrik [128]3 years ago

4 0

the answer is b. it decreases

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(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct

Zarrin [17]

Explanation:

The given data is as follows.

$\Lambda^{o}_{m}$ (NaCl) = $1.264 \times 10^{-2}$

$\Lambda^{o}_{m}$ (H-O=C-ONO) = $1.046 \times 10^{-2}$

$\Lambda^{o}_{m}$ (HCl) = $4.261 \times 10^{-2}$

Conductivity of monobasic acid is $5.07 \times 10^{-2} S m^{-1}$

Concentration = 0.01 $mol/dm^{3}$

Therefore, molar conductivity ( $\Lambda_{m}$ ) of monobasic acid is calculated as follows.

$\Lambda_{m} = \frac{conductivity}{concentration}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}$

= $5.07 \times 10^{-3} S m^{2} mol^{-1}$

Also, $\Lambda^{o}_{m}$ = $\Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}$

= $4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}$

= $4.043 \times 10^{-2} S m^{2} mol^{-1}$

Relation between degree of dissociation and molar conductivity is as follows.

$\alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}$

= 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

Putting the values into the above formula we get the following.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

= $\frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}$

= $0.017973 \times 10^{-2}$

= $1.7973 \times 10^{-4}$

Hence, the acid dissociation constant is $1.7973 \times 10^{-4}$ .

Also, relation between $pK_{a}$ and $K_{a}$ is as follows.

$pK_{a} = -log K_{a}$

= $-log (1.7973 \times 10^{-4})$

= 3.7454

Therefore, value of $pK_{a}$ is 3.7454.

3 0

3 years ago

What properties can you observe about the Sun?

nexus9112 [7]

Energy- The ability to do work or cause a change.
Gravity- A force that pulls objects toward each other.
Light- A kind of energy that you can see.
Sun- The star that is near Earth.
Temperature- A measure of how hot and cold something is.
Transform- To change.

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3 years ago

Read 2 more answers

2. The energy of a photon that has a wavelength of 12.3 nm is _______ J.

klio [65]

I think it is e sorry if I’m wrong

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3 years ago

Explain how you can determine the number of neutrons in the nucleus of an atom of any of the elements listed in the table.

daser333 [38]

Different explanations that lead to the same result

-You need to substract the number of protons from the mass number.

-Mass number - atomic number= number of protons

-Following this equation:

CARBON

atomic number= 6

mass number= 12

mass number= protons + neutrons

12= 6 + x

x= 12-6

x= 6

6 0

3 years ago

dangina [55]

Answer:

Different liquid

Explanation:

<em>The independent variable in the investigation is the different liquid given to the plants.</em>

<u>The independent variable in an experimental investigation is the variable that is supplied by the researcher which directly affects the main variable being measured during the investigation. In other words, the independent variable is a variable that directly affects the dependent variable.</u>

In this case, the dependent variable would be growth determining factors in plants such as height, biomass, number of leaves, etc. while the independent variable would be the different types of liquid given to the plants.

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3 years ago