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3 years ago

What causes ocean water near the equator to be warmer than ocean water farther north

Chemistry

2 answers:

Elena-2011 [213]3 years ago

6 0

Because the water near the equator gets more direct sunlight.

hodyreva [135]3 years ago

3 0

Apex. Sunlight hits directly, so the warmth is more concentrated.

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How many atoms are in 8 grams of helium

Mrrafil [7]

12 x 10^23 atoms, i hope this helps

8 0

2 years ago

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

sertanlavr [38]

Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

4 0

2 years ago

The four fundamental forces are arranged in the increasing order of their relative strength.

natali 33 [55]

Answer:

The correct answer is - both act only between non-atomic particles.

Explanation:

The decreasing order of their relative strength is - the strong force, electromagnetism, weak force, gravity.

so, A would be here = gravity

B would be = weak force

C would be = strong force

The weak and strong forces both are fundamental forces that act on sub-atomic particles only such as quarks.

3 0

3 years ago

What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C

Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = $\frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\$

Now use the molar ratio to find how many moles of NaOH would be required to neutralize $5.5537*10^{-3} mol\\$ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

1 : 2 (we get this from the balanced equation)

$5.5537*10^{-3} mol\\$ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

$c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L$

5 0

3 years ago

Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur:

Gekata [30.6K]

AX(aq)+BY(aq)→no precipitate
AX(aq)+BZ(aq)→precipitate
this two equations imply

AX(aq) is soluble and BY(aq) is insoluble

the answer is
E. BY

5 0

3 years ago