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3 years ago

Write an equation for (2,7) (3,4)

Mathematics

1 answer:

HACTEHA [7]3 years ago

3 0

Answer: y=-3/1x+13

Step-by-step explanation: I just graphed the two points then found there slope and then I finished the line with the slope and then when I knew what was the y-intercept I finished the problem

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Find the value of x. Round your answer to the nearest tenth.

Crazy boy [7]

<h2>The value of x "option A) 12.5" is required answer.</h2>

Step-by-step explanation:

In given figure,

Base (b) = 11 and Angle = 28°

To find, the value of x = ?

We know that,

$\cos A=\dfrac{b}{h}$

Where, h is the hypotaneous = x

⇒ $\cos 28=\dfrac{11}{x}$

⇒ $x=\dfrac{11}{\cos 28}$

The value of $\cos 28$ = 0.8829

⇒ x = $\dfrac{11}{0.8829}$

⇒ x = 12.458

⇒ x ≈ 12.5

∴ The value of x ≈ 12.5

Thus, the value of x "option A) 12.5" is required answer.

7 0

3 years ago

Use numerals instead of words. If necessary, use / for the fraction bar.

Step2247 [10]

Here, AB ║ CD ; EF ⊥ AB

Number of 90 degree formed by the intersections of EF and two parallel lines AB and CD is 8

Hope this helps!

7 0

2 years ago

Ms.Lopez has 4 liters of chemicals that she is going to pour into beakers. Each beaker will have 1/4 of a liter of chemicals, ho

Yakvenalex [24]

It would be 256 because you would do 4 to the power of 4

6 0

2 years ago

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0

3 years ago

Find f(−1) given that f(x)=x3+2x2+3x+4. <br>A. 10 <br>B. -2 <br>C. 2 <br>D. -10

Finger [1]

Answer:

The answer is option C

Step-by-step explanation:

f(x) = x³ + 2x² + 3x + 4

To find f(-1) substitute the value of x that's

- 1 into f(x)

That's

We have the final answer as

Hope this helps you

8 0

3 years ago