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atroni [7]
3 years ago
14

Explained why the thread behaves in this manner​

Physics
1 answer:
Bezzdna [24]3 years ago
7 0
Thread? This? I think you forgot the picture
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A negatively charged particle (charge = -1e) has a velocity of 6.0 × 106 m/s in the positive x direction at a point where the ma
Anni [7]

Answer:

a=2.6x10^{18} m/s^2

Explanation:

v=6.0x10^6 m/s, q=1.6x10^{-19}C, q=9.11x10^{-31}kg

\beta=\beta_x=3.0T, \beta_y=1.5 T, \beta_y=2.0 T

F_b=q*\left[\begin{array}{ccc}i&j&k\\6x10^6&0&0\\3&1.5&2\end{array}\right]

F_b=-1.6x10^{-19}C*[-12x10^6 j + 9x10^6 k]

F_b=m*a

19.2x10^{-13}j-14.4x10^{-13}k=m*a

a=\frac{19.2x10^{-13}}{9.11x10{-31}}-\frac{14.4x10^{-13}}{9.11x10{-31}}

a=2.107 x10^{18}j-1.58x10^{18}k

a=\sqrt{(2.107x10^{18})^2-(1.57x10^{18})^2}

a=2.6x10^{18} m/s^2

7 0
3 years ago
6)<br> Calculate the area of a body which experiences a pressure of 60000 Pa by a force of 120N
Vika [28.1K]

Answer:

area = force by pressure

or, a = 120N by 60000 Pa

or, a= 0.002 m²

4 0
4 years ago
Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

I_3 = 0.920 A

6 0
4 years ago
Write four (4) strategies on how can we manage land use around South Florida. For each strategy, explain it's benefits to the en
a_sh-v [17]

Answer:

What are some ways we can improve on our land use?

- Avoid deforestation and close the forest frontier.

The first-order priority is to end deforestation by closing the "forest frontier" or intact forests, to development.

- Increase agricultural productivity.

- Restore forests and landscapes.

- Reduce food loss and waste.

- Improve diets

3 0
3 years ago
A lab group was given a candle, a match, a strip of cloth, tongs, and a metal can. They were asked to use these materials to mod
Troyanec [42]

Answer:

The materials with which the lab group are to use for the model includes;

i) A candle

ii) A match

iii) A strip of cloth

iv) Tongs

v) A metal can

The processes the lab group are to model are;

a) Conduction

b) Convection

c) Radiation

The procedure the lab group can use to do this is outlined as follows;

1) Tie the piece of cloth around the metal can with a strip of the cloth extending past the bottom of the can

2) Hold the metal can in with the aid of the tongs

3) Light the candle with the match

4) Place the metal can over over the burning candle so that it does not touch the flame

5) While holding the can with the tongs, ensure that the strip of cloth hanging by the side of the can does not come in contact with the flame

Conduction

Conduction heat transfer is observed by the rising temperature of the tongs that is in the contact with the can

Convection

Convection heat transfer is observed by the rising temperature of the can that is placed in the path of the rising convection current from the candle wax

Radiation

Radiation heat transfer is observed by the shrinking of the piece of cloth placed beside the candle flame

Explanation:

3 0
3 years ago
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