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Luda [366]
4 years ago
10

Crests of an ocean wave pass a pier every 10.0 s. if the waves are moving at 5.6 m/s, what is the wavelength of the ocean waves?

Physics
1 answer:
ExtremeBDS [4]4 years ago
4 0
Every 10.0 seconds, a crest of the wave passes the pier. This means that the period of the wave is exactly 10.0 s:
T=10.0 s
which means that the frequency of the wave is
f= \frac{1}{T}= \frac{1}{10.0 s}=0.1 Hz

The wavelength of a wave is related to its frequency by the relationship
\lambda= \frac{v}{f}
where v is the speed of the wave.
In this problem, v=5.6 m/s; if we use the previous formula, we find the wavelength of the wave:
\lambda= \frac{5.6 m/s}{0.1 Hz}=56 m
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In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
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Answer:

D = -4/7 = - 0.57

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Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

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