All categories

3 years ago

Crests of an ocean wave pass a pier every 10.0 s. if the waves are moving at 5.6 m/s, what is the wavelength of the ocean waves?

1 answer:

4 0

Every 10.0 seconds, a crest of the wave passes the pier. This means that the period of the wave is exactly 10.0 s:
$T=10.0 s$
which means that the frequency of the wave is
$f= \frac{1}{T}= \frac{1}{10.0 s}=0.1 Hz$

The wavelength of a wave is related to its frequency by the relationship
$\lambda= \frac{v}{f}$
where v is the speed of the wave.
In this problem, v=5.6 m/s; if we use the previous formula, we find the wavelength of the wave:
$\lambda= \frac{5.6 m/s}{0.1 Hz}=56 m$

You might be interested in

6 use superposition to find voltage v(t) across the 100 ohm resistor

Vinvika [58]

It'll be my pleasure to analyze the circuit, describe my analysis in detail,
and give you a clear, precise, and accurate answer.

As soon as you let me see the circuit diagram, with values marked on
all of its components and power sources.

6 0

3 years ago

A 60kg bicyclist (including the bicycle) is pedaling to the

Fittoniya [83]

a) 4 forces

b) 186 N

c) 246 N

Explanation:

Let's count the forces acting on the bicylist:

1) Weight ( $W=mg$ ): this is the gravitational force exerted on the bicyclist by the Earth, which pulls the bicyclist towards the Earth's centre; so, this force acts downward (m = mass of the bicyclist, g = acceleration due to gravity)

2) Normal reaction (N): this is the reaction force exerted by the road on the bicyclist. This force acts vertically upward, and it balances the weight, so its magnitude is equal to the weight of the bicyclist, and its direction is opposite

3) Applied force ( $F_A$ ): this is the force exerted by the bicylicist to push the bike forward. Its direction is forward

4) Air drag ( $R$ ): this is the force exerted by the air on the bicyclist and resisting the motion of the bike; its direction is opposite to the motion of the bike, so it is in the backward direction

So, we have 4 forces in total.

Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

$F_{net}=ma$

where

$F_{net}$ is the net force

m is the mass of the body

a is its acceleration

In this problem we have:

m = 60 kg is the mass of the bicyclist

$a=3.1 m/s^2$ is its acceleration

Substituting, we find the net force on the bicyclist:

$F_{net}=(60)(3.1)=186 N$

We can write the net force acting on the bicyclist in the horizontal direction as the resultant of the two forces acting along this direction, so:

$F_{net}=F_a-R$

where:

$F_{net}$ is the net force

$F_a$ is the applied force (forward)

$R$ is the air drag (backward)

In this problem we have:

$F_{net}=186 N$ is the net force (found in part b)

$R=60 N$ is the magnitude of the air drag

Solving for $F_a$ , we find the force produced by the bicyclist while pedaling:

$F_a=F_{net}+R=186+60=246 N$

3 0

3 years ago

When you and a friend move a couch to another room you exert a force of 75 N over 5m how much work will you do

sesenic [268]

The work done is 375 J

Explanation:

The work done by a force in moving an object is given by

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement

In this problem,

F = 75 N is the force applied to the couch

d = 5 m is the displacement

Assuming the force applied to the couch is parallel to the motion, $\theta=0$

And so, the work done is

$W=(75)(5)(cos 0)=375 J$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

6 0

3 years ago

The wavelength of light that has a frequency of 1.20 × 1013 s-1 is ________ m.

klio [65]

The relationship between frequency and wavelength for an electromagnetic wave is
$c=f \lambda$
where
f is the frequency
$\lambda$ is the wavelength
$c=3 \cdot 10^8 m/s$ is the speed of light.

For the light in our problem, the frequency is $f=1.20 \cdot 10^{13} s^{-1}$ , so its wavelength is (re-arranging the previous formula)
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{1.20 \cdot 10^{13} s^{-1}}= 2.5 \cdot 10^{-5}m$

8 0

3 years ago

HEEEEELLLLLLLLLLLLLLLLPPPPPPPPPPPPPPP i need to get unstuck

pochemuha

Geyshbdgsggefsgahevayagvdvdgavd

8 0

3 years ago

Read 2 more answers