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2 years ago

Need help with logic question please dont answer if you are just putting a s*upid useless answer

Mathematics

1 answer:

Marianna [84]2 years ago

5 0

Statement 3 must be true!

Mark with crown please!

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ES LA OPERACION DE MOVER LOS EJES COORDENADOS EN EL PLANO COORDENADO A UNA POSICION DIFERENTE, MANTENIENDOLOS PARALELOS A LOS OR

pogonyaev

I don’t not understand what ur asking?

4 0

2 years ago

There are 364 first-grade students in Park Elementary School. If there are 26 more girls than boys, how many girls are there?

wlad13 [49]

Answer:

195

Step-by-step explanation:

If there are x boys, then there are x+26 girls. Hence, we write the equation,

x+(x+26)=364

Solve for x:

2x+26=364

2x-338

x=169

So there are 169+26 =195 girls

5 0

3 years ago

Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te

motikmotik

Given:

There are given that the cos function:

$cos210^{\circ}=-\frac{\sqrt{3}}{2}$

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

$cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}$

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

$\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}$

Then,

Put the value of cos210 degrees into the above function:

So,

$\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}$

Final answer:

Hence, the value of the cos(105) is shown below:

$cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}$

4 0

1 year ago

Shellie spent $10.56 on oranges that cost $0.88 per orange. How many oranges did she purchase?

vlada-n [284]

You have to do 10.56 plus 88 and you will have your answer

6 0

2 years ago

A gumball machine has just been filled with 50 black, 150 white, 100 red and 100 yellow gum balls that have been thoroughly mixe

Andrew [12]

<span>Exactly 33/532, or about 6.2% This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball. There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red. Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133. So the combined probability of both of the 1st 2 gumballs being red is 1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>

6 0

3 years ago