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Aleks04 [339]
2 years ago
14

There are now several effective antimalarial drugs that can treat people who have malaria or prevent them from getting the disea

se altogether. Predict what will happen to the frequency of the sickle cell allele over the next 100 years as these drugs become more widely used by people living in areas where malaria is endemic: _____________ Predict what will happen to the frequency of the sickle cell allele over the next 100 years in areas like Boston MA, where there is no incidence of malaria: __________ stay the same ; stay the same decrease ; increase increase ; increase increase ; decrease decrease ; decrease
Biology
1 answer:
Andrej [43]2 years ago
6 0

Answer:

decrease, decrease

Explanation:

By using antimalarial drugs in order to prevent malaria, the frequency of the sickle cell allele decreases in both areas where malaria is endemic and the areas where no incidence of malaria occurs because there is no necessity of sickle cell allele in the population to prevent malarial disease. Sickle cells have high significance in prevention of malarial diseases so when there is no malaria happens in the population so there is no need for it and the allele slowly removed from the population and decrease occurs in its frequency.

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8 0
2 years ago
4. The Rh blood type response system is controlled by the D allele. The genotypes DD and Dd are Rh (Rh positive); dd is Rh- (Rh
DedPeter [7]

Answer:

A - Frequency of D allele = 0.35

Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

EXPLANATION:

The equilibrium sum of all the allelic frequency of a gene is always 1 and sum of all the genotypic frequency of all the genotype is always 1 - This is according to Hardy-Weinberg.

So p+q =1

p2+ 2pq+q2 =1

where p = frequency of dominant allele

q is the frequency of the recessive allele.

from the question, it was given that there were  170 individual out of 400, which were Rh- negative,

So q2 = 170/400 = 0.425

q= 0.65

Also p+q =1

so p = 1-q

or p = 1-0.65

Hence p =0.35

Frequency of homozgupus for D allele = 0.35*0.35 = 0.1225

Frequency of heterozygous or Dd will be 2pq.

or 2*0.35*0.65 = 0.455

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Frequency of d allele = 0.65

B- Frequency of DD genotype = 0.1225

Frequency of Dd genotype = 0.455

Frequency of dd genotype = 0.425.

C - Total population = 400

Frequency of heterozygous population = 400*0.455 = 183.

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3 years ago
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