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UkoKoshka [18]
3 years ago
13

Balance the equation and state the limiting reagent in the following reaction:

Chemistry
1 answer:
romanna [79]3 years ago
8 0
Hgffvvcbchcgivigcigxgsgixigdfhcgcc fcfuc
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Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types
alexira [117]

Answer:

1) first order

2) zero order

3) second order

Explanation:

For a first order reaction, the concentration of the reactants varies exponentially with the rate of reaction. The curve of a first order reaction shows an exponential relationship between the rate of reaction and the change in the concentration of reactants.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactants. So, regardless of the amount of reactant in solution, the rate of reaction is constant.

For a second reaction, the reaction rate increases in direct proportion to the concentration of the reactant in solution.

6 0
2 years ago
How many moles of HBr are present in 250 ml of a 0.15 M HBr solution?
Fofino [41]

Answer:

0.0375 moles HBr

Explanation:

we are given;

  • Molarity of HBr solution as 0.15 M
  • Volume of the solution as 250 mL

We are required to determine the number of moles;

We need to know that;

Molarity = Moles ÷ Volume

Therefore;

Moles of HBr = Molarity of HBr solution × Volume of solution

Thus;

Moles of HBr = 0.15 M × 0.25 L

                      = 0.0375 Moles

Thus, the number of moles of HBr solute is 0.0375 moles

6 0
3 years ago
Which of the following is the balanced equation for the
NNADVOKAT [17]
A.) is the answer =)
6 0
3 years ago
when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of  CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

8 0
3 years ago
A car with a mass of 1,000 kg is moving at a speed of 20 m/s. What is the car's kinetic energy?
shtirl [24]

The answer would be 200000 J. the equation for kinetic energy is 1/2 mass times velocity squared. 1/2 of 1,000 is 500. and 20*20 is 400. So, multiply 400 by 500, and that gives you your answer,

7 0
2 years ago
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