Answer:
Intermolecular force for oil the dipole-dipole.
Intermolecular force for water hydrogen bonds.
Intermolecular force for vegetable oil nonpolar compound.
Intermolecular force for corn syrup fructose.
Answer: B -Network solids
Ionic solids are held by positive and negative charged ions bonded by electrostatic forces. The electrostatic force is much stronger than dipole–dipole interactions, London dispersion forces, hydrogen bonding.
Molecular solids are held by dipole–dipole interactions, London dispersion forces, or hydrogen bonds. Benzene is an example of this. These inter-molecular force are much weaker than electrostatic force.
The metallic bonds are much weaker than electrostatic force. Similarly, in non-metallic solids the atoms are held by covalent bonds. These covalent bonds are weaker than the electrostatic force.
Thus we can conclude that electrostatic force is the strongest when compared to dipole–dipole interactions, London dispersion forces, hydrogen bonding,covalent and metallic bonds. Thus ionic solids will have the highest melting point as more energy is required to break the ionic bonds as this is the strongest bond compared to the other bonds.
Here, we are going to calculate the mass % of C in the mixture.
What is a Mixture?
A mixture is composed of one or more pure substances in varying composition. There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout.
Given that,
The mass % of CO =35.0% =35.0 g in 100 g mixture
The mass % of CO2 = 65% =65 g in 100 g mixture
Therefore,
The mass of C from CO = 15.007 g C
Similarly,
The mass of C from CO2 = 17.738 g C
Thus, the total mass of C = 15.007 g+17.738 g =32.745 g
Therefore,
The mass % of C= 32.745% =32.7%
Thus, the mass % of C in the mixture is 32.7%
To learn more about carbon-containing compounds click on the link below:
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Answer:
Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless
ramp is equal to the gravitational potential energy of the block at the top of the ramp. This
value is proportional to the square of the block’s velocity at the bottom of the ramp.
Therefore, the block’s final velocity depends on the height of the ramp but not the steepness
of the ramp
Explanation:
Answer is: A) 124 s.
c₀ = 3 mol/L.
c₁ = 0,700 mol/L.
k = 8,8·10⁻³ 1/M·s.
Integrated second order rate law is: 1/c₁ = 1/c₀ + k·t.
k·t = 1/0,700 - 1/3.
0,0088·t = 1,095.
t = 1,095 ÷ 0,0088.
t = 124 s.
c₀ - <span>initial concentration.
c</span>₁ - <span> concentration at a particular time.
k - </span><span>the rate constant.
t - time.</span>
