Answer:
= C3H4N
Explanation:
We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.
We first calculate the number of moles of each element.
Carbon = 90g/12 g/mol
= 7.5 moles
Hydrogen = 11 g/ 1 g/mol
= 11 moles
Nitrogen = 35 g/ 14 g/mol
= 2.5 moles
The we get the mole ratio of the elements;
= 7.5/2.5 : 11/2.5 : 2.5 /2.5
= 3 : 4.4 : 1
= 3 : 4 : 1
Therefore;
The empirical formula will be; C3H4N
Classification ,
correct me if i’m wrong
The unit cell of Aluminum is a face-centered cubic structure. This lattice unit cell consists of 4 atoms per unit cell. The volume of the unit cell is a³ where a is the length of the side of the unit cell. In terms of radius r, volume is equal to:
V = (4r/√2)³
V = (4(0.143×10⁻⁹ m)/√2)³
V = 6.62×10⁻²⁹ m³
Answer:
0.74176 M HCl
Explanation:
1) Write out a balanced equation.
KOH + HCl --> KCl + H2O
2) Calculate #mol KOH in 76.0mL needed for the titration.
1.22 mol KOH in 1000mL
x mol KOH in 76.0mL
x = 0.09272 mol KOH
3) Use the balanced equation ratio (from step 1), 1 mol KOH : 1 mol HCl.
0.09272 mol KOH = 0.09272 mol HCl
4) 125mL of the HCl solution was used for the titration, so find the molarity.
0.09272 mol HCl is in 125mL
x mol HCl in 1000mL
x = 0.74176 mol HCL / 1 L
SO... 0.74176 M HCl is the answer.
*hope this helped*
- A Kind Stranger
