The answer is A. As the first statement is a true statement. Hope this help you
Answer:
weak bonds break and strong bonds form
Explanation:
An exothermic reaction is a chemical reaction in which heat energy is evolved during the reaction process.
Bond formation requires energy while bond breakage releases energy. More energy is needed for the formation of weak bonds as compared to strong bonds.
<em>Hence, when weak bonds break, they release more energy than needed to make a corresponding strong bond leading to the release of the remaining energy as heat.</em>
Answer:
0.453 moles
Explanation:
The balanced equation for the reaction is:
2Fe(s) + 3O2(g) ==> 2Fe2O3
From the equation, mass of O2 involved = 16 x 2 x 3 = 96g
mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2
= 100g
Therefore 96g of O2 produced 100g of Fe2O3
32.2g of O2 Will produce 100x32.2/96
= 33.54g of Fe2O3
Converting it to mole using number of mole = mass/molar mass
but molar mass of Fe2O3 = 26 + (16 X 3)
= 74g/mole
Therefore number of mole of 33.54g of Fe2O3 = 33.54/74
= 0.453 moles
<span>Where is most of the high-level waste from nuclear reactors stored?
</span><span>the ocean</span>
<u>Answer:</u> The final volume of the gas comes out to be 4 L.
<u>Explanation:</u>
To calculate the volume with changing pressure, we use the equation given by Boyle's law.
This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
Mathematically,
(At constant temperature and number of moles)
The equation given by this law is:
![P_1V_1=P_2V_2](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2)
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
![P_1=2.0atm\\V_1=3L\\P_2=1.5atm\\V_2=?L](https://tex.z-dn.net/?f=P_1%3D2.0atm%5C%5CV_1%3D3L%5C%5CP_2%3D1.5atm%5C%5CV_2%3D%3FL)
Putting values in above equation, we get:
![2atm\times 3L=1.5atm\times V_2\\\\V_2=4L](https://tex.z-dn.net/?f=2atm%5Ctimes%203L%3D1.5atm%5Ctimes%20V_2%5C%5C%5C%5CV_2%3D4L)
Hence, the final volume of the gas will be 4 L.