Answer: Infinite solutions
Step 1: Turn this into y=Mx+b form
The current equation is—
-2x+5y=30
Since we want to get y alone on the left side, let’s add 2x on both sides
-2x+5y=30
+2x +2x
____________
5y=2x+30
Step 2: Again, trying to get y alone, we need to divide 5 on both sides
5y=2x+30
/5 /5 /5
________
y=2/5x+6
Step 3: Now that we know how to find y, substitute that in where y is in the equation
-2x + 5(2/5x+6) = 30
-2x + 2x + 30 = 30
30=30
Seeing that you cannot get a specific answer for y when solving, there is an infinite number of solutions
Hope this is right and it helps comment below for more questions :)
Answer:
f(x) = 12x³ - 19x² + 17x - 17
Step-by-step explanation:
We can the numerator by multiplying the denominator by the quotient, and then adding the remainder.
We're given a denominator of 4x - 5
a quotient of 3x² - x + 3
and a remainder of -2
so the original numerator is:
(4x - 5)(3x² - x + 3) - 2
= 12x³ - 4x² + 12x - 15x² + 5x - 15 - 2
= 12x³ - 19x² + 17x - 17
Let's test that by dividing it by 4x -5 with long division:
That matches, so we know our answer's right, and:
f(x) = 12x³ - 19x² + 17x - 17
Answer:
-8
Step-by-step explanation:
you have to make them equivalent so and the one thing missing from the other side of the equation
Let the no. of girls be x and boys be y......
x/y=1/3
=>3x=y ...............(I)
now 4 boys leave the class is then
x/y-4=2/5
=>5x=2y-8
(I)=>5x=2(3x)-8
x=8
now 3x=y
=>y=24
therefore no. of girls is 8 and the no. of boy is 24..............
I have tried my best.....hope i helped............
