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prisoha [69]
3 years ago
7

VL

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

9514 1404 393

Answer:

  B.  No

Step-by-step explanation:

If Nate has 100 bananas when 0 days pass, the relationship between bananas and days cannot be proportional. A proportional relationship would have 0 bananas for 0 days.

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Sindrei [870]
We are asked to sum the two trinomials (-4f^3-5f+16)+(4f^2-f+9). We can start by using the distributive property to remove the parenthesis, giving us -4f^3-5f+16+4f^2-f+9. Next, when we combine like terms, we get \boxed{-4f^3+4f^2-6f+25}. Hope this helped!
8 0
3 years ago
Read 2 more answers
7. In a state lottery, a player must choose 8 of the numbers from 1 to 40. The lottery commission then performs an experiment th
Vlad1618 [11]

Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8

b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4

Step-by-step explanation:

Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40

a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8

There are one in hundred million chances that the draw numbers are precisely the chosen ones.

b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)

8×32

P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.

There are approximately 300,000 chances that 7 of the players numbers are chosen

c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.

P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]

P(at least 6 players numbers are drawn) = 1.84×10^-4.

There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.

5 0
3 years ago
find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

7 0
2 years ago
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