Answer:
It is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg because the probability of this event is large enough.
Step-by-step explanation:
Population mean=μ=3.3.
S.E=0.1.
n=36.
If the probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is larger than the it will be likely. The probability can be calculated by normal distribution because sample size is large enough.
Z-score for 3.2 kg=3.2-3.3/0.1=-1
Z-score for 3.4 kg=3.4-3.3/0.1=1
P(-1<Z<1)=P(-1<Z<0)+P(0<Z<1)
P(-1<Z<1)=0.3413+0.3413
P(-1<Z<1)=0.6826
The probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is 68.26%. So. it is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg as the probability is large enough.
Answer:
Thank you very much :) needed that
5x - 2y = 17
4x - 3y = 8
Try to change one of the equations to isolate a variable, so you can use the new equation and substitute it into the other equation.
5x - 2y = 17
-2y = 17 - 5x
y = -17/2 + 5/2x
Now plug this into the second equation
4x - 3(-17/2 + 5/2x) = 8
4x + 51/2 - 15/2x = 8
8/2x - 15/2x = 16/2 - 51/2
-7/2x = -35/2
x = 5
Plug this into either equation to find y
4x - 3y = 8
4(5) - 3y = 8
20 - 3y = 8
-3y = -12
y = 4
x = 5, y = 4
2*3*6 for large, 2*2*6 for med, 2*2*3 for small with 72 square cm as the surface area
Answer:
peter would win 29 of the 55 tennis matches
Step-by-step explanation:
55-26=29