Answer:
403.176
Explanation:
I hope that the right answer.
Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
ΔG deg will be negative above 7.27e+3 K.
<u>Explanation:</u>
- The ΔG deg with the temperature can be found using the formula and the formula is given below
- ΔG deg = ΔH deg - T ΔS deg
- Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
- -T ΔS deg will be always negative and ΔG deg = ΔH deg will be positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
- solving the equation and substitute ΔGdeg=0
- ΔGdeg = ΔHdeg - T ΔSdeg
- T= ΔHdeg/ΔSdeg
- T=181 kJ / 2.49e-2 kJK-1
- By simplification we get
- T=7.27 × 10^3 K.
- Therefore, Go will be negative above 7.27 × 10^3 K
- Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
- ΔG deg will be negative above 7.27e+3 K.
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The correct answer is E. C6H6 is not soluble in water. This is determined by the polarities of these substances. Benzene is a non-polar substance because it has equal number of electrons sharing a bond thus it does not dissolve in water which is a polar substance.
