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<span>3.10 moles SiO2 (1 mole Si/1 mole SiO2)(6.022 X 1023/1 mole Si) = 1.87 X 1024
</span><span>= 1.20 X 1023 atoms of oxygen.</span>
Answer:
22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C
Explanation:
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:
P * V = n * R * T
where R is the molar constant of the gases and n the number of moles.
In this case you know:
- R= 0.082

- T= 24 °C= 297 °K (being 0°C=273°K)
Replacing:

Solving:

n=0.708 moles
Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass= 22.656 grams
<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>