Find the mass, in grams, of 1.00 x 1023 molecules of CO2

Which of the following explains why the lab safety policy specifically addresses loose clothing, contact lenses, and large, loos

valentina_108 [34]

Answer:

b. Loose clothing and jewelry is more likely to impede movement, or accidentally knock materials over, causing a spill or other accident.

Explanation:

Hello,

During the laboratories, a high dexterity is required, thus, such accessories, when you move or change your duty, could touch other materials or act out of your control resulting in spillages and constricting your proper movements and skills, that is why considering the lab safety policy, we must take those artifacts away from the chemistry lab.

Best regards.

3 0

3 years ago

Calculate the solubility in g/l of lead (ii) fluoride in water at 25 oc if ksp of pbf2 is 4. 1 x 10-8.

Svetlanka [38]

The solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L in water at 25°C.

At a specific solution temperature, a solid salt compound can entirely dissolve in pure water up to a predetermined molar solubility limit. The dissociation stoichiometry ensures that the molarities of the constituent ions are proportionate to one another. The saturable nature of the solution causes them to also coexist in a solubility equilibrium with the solid component. At this temperature, a solubility product constant Ksp is calculated using the solubility product of their molarity values.

Lead (II) fluoride has the following solubility equilibrium for its saturated solution:

$PbF_2(s)$ ⇄ $Pb^2^+ (aq) + 2F^- (aq)$

$K_s_p = [Pb^2^+][F^-]^2$

This compound dissociates in a 1:2 ratio of ions. For the compound dissolved in pure water, the Ksp is expressed in terms of the molar solubility "x" as:

$K_s_p = (x) (2x)^2\\$

$K_s_p = 4x^3$

Here,

$K_s_p= 4.1$ × $10^-^8$

4.1 × 10⁻⁸ = 4 x³

x³ = 1.025 × 10⁻⁸

x³ = 10.25 × 10⁻⁹

x = 2.17 × 10⁻³ g/L

Therefore, the solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L.

Learn more about solubility here:

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6 0

2 years ago

Which equation shows how to calculate how many grams (g) of KCI would be

Semenov [28]

Answer:

C or D

Explanation:

Hope it helped a little bit

3 0

3 years ago

The triple point of nitrogen occurs at a temperature of 63.1 K and a pressure of 0.127 atm. Its normal boiling point is 77.4 K.

yulyashka [42]

Nitrogen has a normal boiling point of 77.4 K and a melting point (at 1 atm) of 63.2 K. Its critical temperature is 126.2 K, and its critical pressure is 2.55 * 104 torr. It has a triple point at 63.1 K and 94.0 torr.

<h3>What is the triple point?</h3>

The temperature and pressure at which the solid, liquid, and vapour phases of a pure substance can coexist in equilibrium.

- Normal melting point: 63.2 K.

- Normal boiling point: 77.4 K.

- Triple point: 0.127 atm and 63.1 K.

- Critical point: 33.5 atm and 126.0 K.

In such a way:

- N2 does not exist as a liquid at pressures below 0.127 atm: that is because below this point, solid N2 exists only (triple point).

- N2 is a solid at 16.7 atm and 56.5 K: that is because it is above the triple point, below the critical point and below the normal melting point.

- N2 is a liquid at 1.00 atm and 73.9 K: that is because it is above the triple point, below the critical point and below the normal boiling point.

- N2 is a gas at 0.127 atm and 84.0 K: that is because it is above the triple point temperature at the triple point pressure.

Learn more about triple point here:

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5 0

2 years ago

What is this element?

scoray [572]

Answer:

stuff around the earth

Explanation:

like water,fire,wind,and earth/plants

4 0

2 years ago