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salantis [7]
2 years ago
15

Find the mass, in grams, of 1.00 x 1023 molecules of CO2

Chemistry
1 answer:
Ostrovityanka [42]2 years ago
8 0

Answer:

Cosimo

Explanation:

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Aspirin, like many pharmaceutical drugs, can access the cell because it is a weak acid. This occurs because Choose one: A. it is
sleet_krkn [62]

Answer:

Correct answer is (D). as a weak acid it can cross the membrane when in its uncharged form.

Explanation:

Aspirin (acetylsalicylic acid, ASA) is an analgesic and anti-inflammatory agent use in the treatment of gentle to moderate pain, inflammation and fever. It is absorb in the stomach and intestine in an unchanged form.

6 0
3 years ago
What is the composition of Gilsonite?
nekit [7.7K]

Answer:

Roughly C100 H140 N3 O

Explanation:

Gilsonite is a bituminous product that resembles shiny black obsidian.

It contains more than 100 elements.

Its mass composition varies but is approximately 84 % C, 10 % H, 3 % N, and 1 % O.

Its empirical formula is roughly C100 H140 N3 O.

3 0
3 years ago
Evaluate the carbon dioxide molecule. Explain how to determine if double or triple bonds exist in the molecule.
S_A_V [24]

Answer:

It contain double Bond.

Explanation:

To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.

4 0
3 years ago
How many molecules of CO are produced when 2.73 moles of HPO3 react? 4HPO3 + 12C ----> 2H2 + 12CO + P4
Zina [86]
According to the balanced chemical equation:
4 HPO₃ + 12 C → 2 H₂ + 12 CO + P₄
4 moles of HPO₃       ---gives---> 12 moles of CO
2.73 moles of HPO₃  ---gives---> ? moles of CO
so number of moles of CO = \frac{(2.73 * 12)}{4} = 8.19 moles of CO
Number of molecules of CO = number of moles * Avogadro's number
                                       = 8.19 * (6.022 * 10²³) = 4.93 * 10²⁴ molecules
3 0
3 years ago
The molecule ethylbenzene is considered an....
noname [10]
D. Cycloalkene
________________________
5 0
3 years ago
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