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scZoUnD [109]
3 years ago
12

Sulfur trioxide can react with atmospheric water vapor to form sulfuric acid that falls as acid rain. Calculate the mass in gram

s of 3.65 × 1020 molecules of SO3.
Chemistry
1 answer:
Natali [406]3 years ago
4 0

<u>Answer:</u> The mass of sulfur trixoide is 0.0485 g

<u>Explanation:</u>

We are given:

Molecules of sulfur trixoide = 3.65\times 10^{20}

According to mole concept:

6.022\times 10^{23} number of molecules are present in 1 mole of a compound

So, 3.65\times 10^{20} number of molecules will be present in = \frac{1}{6.022\times 10^{23}}\times 3.65\times 10^{20}=6.06\times 10^{-4}mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sulfur trixoide = 6.06\times 10^{-4}mol

Molar mass of sulfur trioxide = 80 g/mol

Putting values in above equation, we get:

6.06\times 10^{-4}mol=\frac{\text{Mass of }SO_3}{80g/mol}\\\\\text{Mass of }SO_3=(6.06\times 10^{-4}mol\times 80g/mol)=0.0485g

Hence, the mass of sulfur trixoide is 0.0485 g

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When you combine 50.0 mL of 0.100 M AgNO3 with 50.0 mL of 0.100 M HCl in a coffee-cup calorimeter, the temperature changes from
RideAnS [48]

Answer : The enthalpy of reaction (\Delta H_{rxn}) is, 67.716 KJ/mole

Explanation :

First we have to calculate the moles of AgNO_3 and HCl.

\text{Moles of }AgNO_3=\text{Molarity of }AgNO_3\times \text{Volume}=(0.100mole/L)\times (0.05L)=0.005mole

\text{Moles of }HCl=\text{Molarity of }HCl\times \text{Volume}=(0.100mole/L)\times (0.05L)=0.005mole

Now we have to calculate the moles of AgCl formed.

The balanced chemical reaction will be,

AgNO_3(aq)+HCl(aq)\rightarrow AgCl(s)+HNO_3(aq)

As, 1 mole of AgNO_3 react with 1 mole of HCl to give 1 mole of AgCl

So, 0.005 mole of AgNO_3 react with 0.005 mole of HCl to give 1 mole of AgCl

The moles of AgCl formed  = 0.005 mole

Total volume of the solution = 50.0 ml + 50.0 ml = 100.0 ml

Now we have to calculate the mass of solution.

Mass of the solution = Density of the solution × Volume of the solution

Mass of the solution = 1.00 g/ml × 100.0 ml = 100 g

Now we have to calculate the heat.

q=m\times C\Delta T=m\times C \times (T_2-T_1)

where,

q = heat

C = specific heat capacity = 4.18J/g^oC

m = mass = 100 g

T_2 = final temperature = 24.21^oC

T_1 = initial temperature = 23.40^oC

Now put all the given values in the above expression, we get:

q=100g\times (4.18J/g^oC)\times (24.21-23.40)^oC

q=338.58J

Now  we have to calculate the enthalpy of the reaction.

\Delta H_{rxn}=\frac{q}{n}

where,

\Delta H_{rxn} = enthalpy of reaction = ?

q = heat of reaction = 338.58 J

n = moles of reaction = 0.005 mole

Now put all the given values in above expression, we get:

\Delta H_{rxn}=\frac{338.58J}{0.005mole}=6771.6J/mole=67.716KJ/mole

Conversion used : (1 KJ = 1000 J)

Therefore, the enthalpy of reaction (\Delta H_{rxn}) is, 67.716 KJ/mole

4 0
3 years ago
Question 1 (4 points)
lutik1710 [3]

B= CH2O

empirical formula using the simplest ratio of atoms in the compound

4 0
3 years ago
How do I find density
skad [1K]
Divide mass by the volume to find density.
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3 years ago
Weight of one mole of carbon = 12.01 g Weight of one mole of oxygen = 16.00 g The molecular weight (gram formula weight) for CO
murzikaleks [220]

Answer:

28.01g

Explanation:

Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.

The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .

The molecular weight of the compound CO is therefore

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That’s = 12.01g + 16.00g

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Therefore, the molecular weight of CO is 28.01g

4 0
4 years ago
Valance shell example..​
Natali5045456 [20]

Answer:

<h2>Oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.</h2>

<h3>Valence electrons are the electrons in the outermost shell, or energy level, of an atom. </h3>

<h3>Configuration of oxygen's valence electrons as 2s²2p⁴.</h3>

Explanation:

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