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Butoxors [25]
3 years ago
10

A semi-circle is connected to an isosceles triangle. The radius of the semi-circle is 2 inches, and the height of the triangle i

s 6 inches. Find the area of the composite figure. My kid needs help with this.
Mathematics
1 answer:
NikAS [45]3 years ago
5 0

Answer:

Hi

Step-by-step explanation:

Is there like a multiple choice so I could answer it:)

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l-4x+4l
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The answer is the first one:

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A train travels 70 kilometers in 4 hours, and then 55 kilometers in 3 hours. What is its average speed?
Naya [18.7K]

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Step-by-step explanation:


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maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

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1 year ago
What is -5/8 × 2/3 than divide by 2
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Answer:

-5/24

Step-by-step explanation:

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3 years ago
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