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LUCKY_DIMON [66]
4 years ago
12

A paper clip released gently into the liquid settles at the bottom of the cylinder. What best compares the densities of the subs

tances?
The clip is denser than the three liquids, and water is denser than oil.
Oil is denser than water but less dense than the clip.
Corn starch is denser than the other liquids and the clip.
Oil is denser than the other liquids, and all liquids are denser than the clip.​
Chemistry
1 answer:
Dmitry_Shevchenko [17]4 years ago
8 0

Answer:

C.

Explanation:

Objects and liquids float on liquids of a higher density and sink through liquids of lower density. the water and corn starch sank under the oil as well so that means they are denser. The paper clip sank through all three liquids also. Hence, the answer would be the clip is denser than the three liquids, and water is denser than oil.

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You have a hard glass flask that you plug up with a stopper at room temperature (25 C) and an internal pressure of 1 atm. If you
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pressure of 0atm

Explanation:

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What pattern appears in the horizontal arrangement (rows) of the elements in the Periodic Table, moving from left to right?
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The horizontal rows in the periodic table are periods, while the vertical rows are called groups. The elements moving from left to right in "periods" have increasing atomic numbers.
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3 years ago
Which of the following coefficients are needed to balance the combustion reaction of ethanol?
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5 0
3 years ago
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
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