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son4ous [18]
3 years ago
8

A 15.0 g piece of copper wire is heated, and the temperature of the wire changes from 12.0oC to 79.0oC. The amount of heat absor

bed is 775 cal. What is the specific heat of copper?
Chemistry
1 answer:
Allushta [10]3 years ago
7 0

Answer:

The specific heat of the copper is 0.771 cal/ grams °C

Explanation:

Step 1: Data given

Mass of the piece of copper = 15.0 grams

The temperature of the wire changes from 12.0 °C to 79.0 °C

The amount of heat absorbed is 775 cal

Step 2: Calculate the specific heat of copper

Q = m*c*ΔT

⇒with Q = the heat absorbed = 775 cal

⇒with m = the mass of the copper = 15.0 grams

⇒with c = the specific heat of copper = TO BE DETERMINED

⇒with ΔT = The change in temperature = 79.0 °C - 12.0 °C = 67.0 °C

775 cal = 15.0 grams * c * 67.0 °C

c = 0.771 cal/gm °C

The specific heat of the copper is 0.771 cal/ grams °C

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Another chemistry question i’m not good at this at all:( has me stressed
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Answer:

Average atomic mass = 15.86 amu.

Explanation:

Given data:

Number of atoms of Z-16.000 amu = 205

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Solution:

Total number of atoms = 205 + 15 = 220

Percentage of Z-16.000 = 205/220 ×100 = 93.18%

Percentage of Z-14.000 = 15/220 ×100 = 6.82 %

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Average atomic mass  = (93.18×16.000)+(6.82×14.000) /100

Average atomic mass =  1490.88 + 95.48 / 100

Average atomic mass =  1586.36 / 100

Average atomic mass = 15.86 amu.

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growing only enough crops for food to fed the family

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Answer : The value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

Explanation :

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The oxidation-reduction half cell reaction will be,

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

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To calculate the E^o_{(Cu^{2+}/Cu)} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

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Putting values in above equation, we get:

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Hence, the value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

8 0
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