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BabaBlast [244]
3 years ago
6

What is the distance between (12.-7) and (-3, -7)? ​

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Step-by-step explanation:

distance between (12.-7) and (-3, -7)

\sqrt{ {(12  +  3)}^{2} +  {0}^{2}  }

=12+3

=15 units

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While researching Facts on the planet earth Kate learned that a true earth day is about 23.93 hours long how many hours are in 2
HACTEHA [7]

Answer:

335.02

Step-by-step explanation:

Just multiply 23.93 by 14 which is 2 weeks

4 0
3 years ago
Write the equation of this line in Point-Slope Form.​
Leona [35]

Answer:

y -3 = (-1/2)(x - 5)

Step-by-step explanation:

Slope of line:  Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1.  Thus, the slope is m = -1/2.

Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:

y -3 = (-1/2)(x - 5)

5 0
2 years ago
I need help ASAP!!!please help
muminat
Use 6 triangles then 2 square so you will only be using a total of 4 square and 12 triangles
8 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
Read 2 more answers
What i -5 5/12 written a a decimal
Helen [10]
-5 5/12 =-5.416
(: :)
(:
7 0
3 years ago
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