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BabaBlast [244]
3 years ago
6

What is the distance between (12.-7) and (-3, -7)? ​

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Step-by-step explanation:

distance between (12.-7) and (-3, -7)

\sqrt{ {(12  +  3)}^{2} +  {0}^{2}  }

=12+3

=15 units

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Please help
Ymorist [56]

Part C:

y = total cost

M = minutes


You can talk on the phone only 100 minutes per month

Company A:

y = 0.04M + 5

y = 0.04(100) + 5

y = 4 + 5

y = 9             $9 per month


Company B:

y = 0.10M + 2

y = 0.10(100) + 2

y = 10 + 2

y = 12          $12 per month


Company A offers the best deal because at Company A you have to pay $9 for 100 minutes per month, and at Company B you have to pay $12 for 100 minutes per month, so you have to pay $3 less.


Part D:

1.) With a budget of $30, Company A would allow me to talk longer on the phone. I know this because for Company A, you pay $3 less per month for the same amount of minutes as Company B. This means that I will save more money with Company A, and I can buy more minutes. (something like this)


6 0
3 years ago
1/128 = 2^(5x+3) <br><br><br>anybody know what x is
Jet001 [13]

Answer:

{2}^{(5x + 3)}  =  \frac{1}{128}  \\  {2}^{(5x + 3)}  =  \frac{1}{ {2}^{7} }  \\  {2}^{(5x + 3)}  =  {2}^{ (- 7)}  \\ 5x + 3 =  - 7 \\ 5x =  - 7 - 3 \\ 5x =  - 10 \\ x =  \frac{ - 10}{5}  \\  \boxed{x =  - 2}

  • <u>x = -</u><u>2</u> is the right answer.
5 0
3 years ago
A right rectangular pyramid is sliced vertically (down) at the red line by a plane not passing through the vertex of the pyramid
crimeas [40]

The cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a <u>rectangle</u>. Hence, <u>4th option</u> is the right choice.

If the peak of the rectangular pyramid is directly above the center of the base, it creates a perpendicular to the base, indicating the height of the pyramid. This type of rectangular pyramid is known as the right rectangular pyramid.

A rectangle is a quadrilateral, that is a closed figure with 4 line segments, with all four interior angles at 90°.

When we slice a right rectangular pyramid vertically down at the red line by a plane, not passing through the vertex, of the pyramid will be a dilated image of its base.

A dilated image is an enlarged or diminished image of the preimage, similar with all angles.

Thus, the cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a <u>rectangle</u>. Hence, <u>4th option</u> is the right choice.

Learn more about right triangular pyramids at

brainly.com/question/27658401

#SPJ4

For complete question, refer to the attachment.

5 0
2 years ago
Given the following relations on the set of all integers where (x,y)∈R if and only if the following is satisfied. (Check ALL cor
Wewaii [24]

Answer:

a) symmetric

b) symmetric, reflexive, transitive

c) antisymmetric

d) symmetric

Step-by-step explanation:

(a) x+y = 0

- this relation is not reflexive, because the only element that relates with itself is 0. x+x = 2x, x+x = 0 only if 2x = 0, hence x = 0. Since 0 relates with itself, then the relation isnt irreflexive either.

Note that for x,y such that x R y, we have that x+y = 0, therefore, y = -x.

-If x,y,z are such that x R y, y R z, then y = -x, z = -y = -(-x) = x. In general x does not relate with z because z=x and the relation isnt reflexive, thus the relation is not transitive. For example, if x = z = 2, y = -2, we have that xRy, yRz, but x does not relate with z.

- This realtion is symmetric due to the commutativity of the sum. If xRy, then  x+y = 0, and y+x = x+y = 0, hence yRx. Therefore, the relation cant be antisymmetric, because every element different from 0 relates to its opposite. For example 2R-2, -2R2 but 2 ≠ -2.

b) x-y is an integer

Since we are taking the substraction of two integers, the result will always be integer. Hence, every pair of elements relate within each other. As a result, the relation is symmetric, reflexive and transitive. However, it is not irreflexive nor antisymmetric, because for example 4R4, and 4R8, 8R4, but 4 is not 8.

c) x = 2y

Note that x = 2x only if x = 0, so the relation is neither reflexive nor irreflexive.

The relation is not symmetric, for example, 4R2 because 4 = 2*2, but 2 does not relate with 4, because 4*2 = 8. However, the relation is antisymmetric, because if xRy, yR2, we have

  • x = 2y
  • y = 2x = 2(2y) = 4y

since y = 4y, y should be 0, and x = 2*0 = 0. Therefore x=y = 0. The relation is antisymmetric.

The relation isnt transitive: 2R4, 4R8, but 2 does not relate with 8 because 8*2 = 16.

d) xy>1

since 0² = 0, 0 does not relate with itself, hence the relation is not reflexive. It is not irreflexive either, because, for example, 2*2 = 4 > 2, thus 2 relates with itself.

The relation is not transitive: 1 relates with every integer greater than itself, but it does not relate with itself, for example 1R7 and 7R1 because 1*7=7*1 = 7 > 1, but 1*1 = 1, it is not greater than 1, hence 1 doesnt relate with itself. This also shows that the relation is not antisymmetric either, because 1R7, 7R1 but 1≠7. The relation, however, is symmetric due to the commutativity of the product. If xy > 1, then yx = xy >1 as well.

I hope that works for you!

8 0
4 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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