You just need to multiply 5 x 7 x 3 = 105 combination of outfits
(x^4 - 9)(x^3 + 9)
This is a binomial * binomial. Use the FOIL method for multiplying.
First, outer, inner, last.
x^4 * x^3 = x^7
x°^4 * 9 = 9x^4
-9 * x^3 = -9 x^3
-9 * 9 = -81
Putting it back together.
x^7 +9x^4 -9x^3 - 81
EXPLANATION
Since we have the function:

Vertical asymptotes:

Taking the denominator and comparing to zero:

The following points are undefined:

Therefore, the vertical asymptote is at x=-5
Horizontal asymptotes:










In conclusion:
Answer:
y=1/2x-2
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Answer:
b) Circle
Step-by-step explanation:
<em>All</em> of the conic sections have vertices and foci. These features are not usually talked about for a circle, so perhaps "circle" is the expected answer.
__
A circle is a special case of ellipse with eccentricity 0. Its foci are coincident at its center, and its vertices are the ends of any pair of perpendicular diameters.