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STatiana [176]
3 years ago
14

Hi guys can you answer 2 math question ​

Mathematics
2 answers:
Anika [276]3 years ago
6 0
2) 8/10 7/10 3/10 5/10
Gnom [1K]3 years ago
4 0

2.

1st pair:

\frac{8}{10} \:  \:  and \:  \:  \frac{4}{5}

2nd pair:

\frac{7}{10}  \:  \: and \:  \:  \frac{35}{50}

3rd pair:

\frac{3}{10}  \:  \: and \:  \:  \frac{30}{100}

4th pair:

\frac{1}{2}  \:  \: and \:  \:  \frac{5}{10}

Leftover:

\frac{4}{10}  \\

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A man travelled 3/5 of his journey by rail, 1/4 by a taxi, 1/8 by a bus and the remaining 2 km on foot.What is the length of his
docker41 [41]
Hello friend,here is the solution

<span>Let x be the total distance </span>

<span>Distance travelled by rail = 3/5 x </span>

Distance travelled by taxi = 1/4 x

<span>Distance travelled by bus = 1/8 x </span>

<span>The equation we obtain is </span>
========================

<span>x = 3/5 x + 1/4 x + 1/8 x +2 </span>

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<span>hope this solution helps you......</span>
7 0
3 years ago
One fifth as a percentage
Sidana [21]
When dealing with percentages it is often much easier to convert it to a decimal (mostly because a lot of people are uncomfortable working with fractions) but in this case, I suggest dividing 1 into 5 [hint hint fractions are just glorified division in the long run] and after you have done that multiply by 100. This will get you your answer. 
4 0
3 years ago
Related rates(calculus)
telo118 [61]

Answer:

The volume increases at a rate of 125663.71 mm^ 3 / s

Step-by-step explanation:

The rate of change of the radius with respect to time is 4 mm / s.


So:


\frac{dr}{dt} = 4mm / s

Now we must find a relationship between the volume of a sphere and its radius.


The equation of the volume of a sphere is:


V = \frac{4}{3}\pi r^ 3

So:


\frac{dV}{dt} = \frac{4}{3}\pi * 3r ^ 2 * \frac{dr}{dt}\\\frac{dV}{dt} = 4\pi r ^ 2 * 4\\\frac{dV}{dt} = 16\pi r ^ 2

The diameter of the sphere is 100 mm. Therefore its radius is 100/2 = 50 mm.


So:


\frac{dV}{dt} = 16\pi (50) ^ 2\\\frac{dV}{dt} = 40000\pi mm^3 / s


The volume increases at a rate of :

40000 π mm ^ 3 / s = 125663.71 mm^3/s

7 0
3 years ago
In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg
Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

6 0
3 years ago
PLEASE HELP!!! 30 POINTS!!!!!! D: 4 Questions!! It's comparing functions!!
NemiM [27]
Ohh, sorry friend because I don't know
7 0
3 years ago
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