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natulia [17]
3 years ago
7

Can you please tell me where I did a mistake.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
Last one should be less than 3/4
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Solve x2 – 10x + 25 = 35 for x.
Galina-37 [17]

x^2-10x+25=35\\\\x^2-2\cdot5\cdot x + 5^2=35\ \ \ |\text{use:}\ (a-b)^2=a^2-2ab+b^2\\\\(x-5)^2=35\to x-5=\pm\sqrt{35}\ \ \ |+5\\\\\boxed{x=5-\sqrt{35}\ \vee\ x=5+\sqrt{35}}


\text{other method}\\\\x^2-10x+25=35\\\\x^2-5x-5x+25=35\\\\x(x-5)-5(x-5)=35\\\\(x-5)(x-5)=35\\\\(x-5)^2=35\\.....

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Is this an acute,obtuse or reflex angle
Ludmilka [50]
It will be a reflex angle

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frosja888 [35]

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Step-by-step explanation:

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75/100, 20/100, 8/1000

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