Answer:
1000 times
First, we estimated the Sun's width in terms of the Earth's breadth, then the Star's width in terms of the Earth's breadth, and for comparison, we did simple division, which revealed that the Star KW Sagittarii is 1000 times wider than the Sun.
Answer:
180 boxes
Step-by-step explanation:
The rate of change is 10 boxes per hour, so if you multiply 10 times 18 you will get 180 which is the answer.
Add 4 to both sides
w = -6
(x-4)(x-3) so what you do is
x -4
x x^2 -4x
-3 -3x 12
x^2-7x+12
your answer would be -7x
Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have

So, from equation (i), we have

Now, when Y = 11, then from equation (ii), we get

Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.