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kykrilka [37]
3 years ago
15

Please help I already asked this question but they told me b and e but it was wrong. This is my last chance pleassssse help

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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How do you graph y=1/9x+12
cluponka [151]
Y-intercept : 12
use the rise over run method
x: 0 1
y: 12 109/9
8 0
3 years ago
Help plz I don’t get it
laila [671]

(I will do the first two parts of each question)

1a. 13 is only divisible by 1 and 13, so they are its factors.

1b. 30 can be divided by 1 and 30, and 2*15=30, 3*10=30, and 5*6=30, so 30's factors are 1, 2, 3, 5, 6, 10, 15, and 30.

2. 75's factors are: 1, 3, 5, 15, 25, and 75. So, there can be 75 piles of 1, 25 piles of 3, 15 piles of 5, etc. (3 more)

3a. 3*1=3, 3*2=6, 3*3=9, etc. so the first 5 multiples of 3 are: 3, 6, 9, 12, 15

3b. Same as before, so: 10, 20, 30, 40, 50

3 0
3 years ago
Read 2 more answers
You have been asked to build a scale model of your school out of toothpicks. Imagine your school is 30 feet tall. Your scale is
Black_prince [1.1K]
A) You will need 6 toothpicks.
B) You will need 5 cotton swabs. (rounded up)
3 0
3 years ago
Pls help me and thank ya!!
algol13

Answer:

Option 1

Step-by-step explanation:

Rational numbers do not have infinite decimals.

Option 1:

-5, 3/4 and √49 are all rational. Correct

√49 = 7

3/4 = 0.75

-5 = -5

Option 2:

1/4 = 0.25

5 = 5

√12 = 3.4641...

Incorrect

Option 3:

-1/2 = -0.5

-3 = -3

√8 = 2.82841...

Incorrect

Option 4:

1/7 = 0.142857...

9 = 9

√11  = 3.31662...

Incorrect

5 0
3 years ago
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
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