The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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1/2 as a decimal is 0.5 or .5
In the first statement, it is false. -2+14 would not add up to 16.
In the third statement, it is false. -8+-2 would not add up to 16.
In the fourth statement, it is false. -2-14 would not add up to 16.
So the second statement is true -2+18=16.
Answer:
2"(3a+2)+(2a-1)"
Step-by-step explanation:
2(5a+1)
10a+2
<span>Give all the 19 apples to each one of them and give the basket to the last child with the apple still inside it.</span>
