Answer:
The total distance is equal to the change in total position of the person, but the displacement of the person is zero.
Explanation:
- The distance is the total change in the positions of the toy robot. it is having only magnitude and it is a scalar quantity.
- The displacement is the difference between the final and initial position of the toy robot. it is a vector quantity having magnitude and direction
- Since the distance is the change in positions, so the magnitude of the distance will be equal to the up and down distance covered.
- If the toy robot travels in a straight line path and returns back to its original location, the magnitude of the distance and displacement doesn't depend on the speed of the toy robot.
Answer:
4.8 ton
Explanation:
We are given that
Mass,m=77 ton
Displacement,s=3500 ft
We have to find the force parallel to the incline would be required to hold the monolith on this causeway.
The force parallel to the incline would be required to hold the monolith on this causeway=
Using the formula
The force parallel to the incline would be required to hold the monolith on this causeway=
Answer:
younger than 50,000 years and older than 100 years
Explanation:
Carbon-14 is produced in the upper atmosphere when cosmic rays bombard nitrogen atoms. The ensuing atomic interactions create a steady supply of c14 that rapidly diffuses throughout the atmosphere. Plants take up c14 along with other carbon isotopes during photosynthesis in the proportions that occur in the atmosphere. animals acquire c14 by eating the plants (or other animals). During the lifetime of an organism, the amount of c14 in the tissues remains at an equilibrium since the loss (through radioactive decay) is balanced by the gain (through uptake via photosynthesis or consumption of organically fixed carbon). However, when the organism dies, the amount of c14 declines such that the longer the time since death the lower the levels of c14 in organic tissue. This is the clock that permits levels of c14 in organic archaeological, geological, and paleontological samples to be converted into an estimate of time.
half-life of radiocarbon is actually 5730 ± 40 years
<u>Since there are practical limits to the age range of the method, most samples must be younger than 50,000 years and older than 100 years.</u>
Answer: a) 50
Explanation:
This implies that the controller must be visible at not more than 50ft which is 15m
Answer:
Δd = 7.22 10⁻² m
Explanation:
For this exercise we must use the dispersion relationship of a diffraction grating
d sin θ = m λ
let's use trigonometry
tan θ = y / L
how the angles are small
tant θ = sinθ /cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
y = m λ L / d
let's use direct ruler rule to find the distance between two slits
If there are 500 lines in 1 me, what distance is there between two lines
d = 2/500
d = 0.004 me = 4 10⁻⁶ m
diffraction gratings are built so that most of the energy is in the first order of diffraction m = 1
let's calculate for each wavelength
λ = 656 nm = 656 10⁻⁹ m
d₁ = 1 656 10⁻⁹ 1.7 / 4 10⁻⁶
d₁ = 2.788 10⁻¹ m
λ = 486 nm = 486 10⁻⁹ m
d₂ = 1 486 10⁻⁹ 1.7 / 4 10⁻⁶
d₂ = 2.066 10⁻¹ m
the distance between the two lines is
Δd = d1 -d2
Δd = (2,788 - 2,066) 10⁻¹
Δd = 7.22 10⁻² m
