Correct answer is A.
In a parallel circuit, the voltage is same across all the branches however the current in each branch is different and depends on the resistance of that branch. The higher the resistance, the lower the current.
In a series circuit, the voltage across each resistive element is different and depends on the resistance of that element. Higher the resistance, larger will be the voltage drop. However, the current throughout the series circuit is the same as there is only path in a series circuit.
Points to Remember:
1) In series circuit current remains the same and voltage varies
2) In parallel circuit voltage remains the same and current varies
Answer:
1.12×10⁻⁵ C and 2.24×10⁻⁵ C.
Explanation:
From coulomb's law,
F = kAB/r².............................. Equation 1
Where F = Force exerted by each charge, A = charge at point A, B = charge at point B, r = distance of separation between the points, k = constant of proportionality.
Given: F = 47 N, r = 22 cm = 0.22 m.
Constant: k = 9.0×10⁹ Nm²/C²
Let: B = q, the A = 2q.
Substituting these values into equation 1,
47 = 9.0×10⁹(q×2q)/0.22²
47 = 18×10⁹(q²)/0.0484
q² = (47×0.0484)/(18×10⁹)
q² = 0.126×10⁻⁹
q² = 1.26×10⁻¹⁰
q = √( 1.26×10⁻¹⁰)
q = 1.12×10⁻⁵ C
The charge at point A = 2q = 2× 1.12×10⁻⁵ = 2.24×10⁻⁵ C.
Hence the charges are 1.12×10⁻⁵ C and 2.24×10⁻⁵ C.
Answer:
Explanation:
c )
First of all we shall calculate the velocity of bullet just after the collision with the pendulum by applying conservation of momentum law.
v₂ = mv₁ / ( m + M )
v₂ is velocity after the collision , m is mass of bullet v₁ is velocity of bullet and M is mass of pendulum.
v₂ = .030 x 185 / 3.18
= 1.745 m /s
Let the angle of the pendulum’s maximum displacement with the vertical be θ
height attained by the pendulum h = L ( 1 - cosθ) ; L is the length of the string.
Applying conservation of mechanical energy law
mgh = 1/2 m v₂²
m is mass of (bullet+ pendulum) , v₂ is its velocity
g L ( 1 - cosθ) = v₂² / 2
9.8 x 2.85 ( 1 - cosθ) = 1.745² / 2
( 1 - cosθ) = .0545
cosθ = .9455
θ = 19 degree
a ) The vertical component of the pendulum’s maximum displacement.
L ( 1 - cosθ)
= 2.85 ( 1 - .9455
= .155 m
b ) Horizontal component : L sin18
= 3.15 x .30
= .97 m .
Answer:
The distance the plane covered while it was accelerating is 80,633.3 m
Explanation:
Given;
initial velocity of the plane, u = 90 m/s
acceleration of the plane, a = 1.5 m/s²
final velocity of the plane, v = 500 m/s
The distance covered by the plane is given as;
v² = u² + 2ad
where;
d is the distance covered by the plane;
500² = 90² + 2(1.5)d
500² - 90² = 3d
241900 = 3d
d = 241900 / 3
d = 80,633.3 m
Therefore, the distance the plane covered while it was accelerating is 80,633.3 m
Answer:
3
Explanation:
a linear positive relationship
