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Stells [14]
4 years ago
6

What type of energy conversion occurs at the moment fireworks explode?

Physics
2 answers:
allsm [11]4 years ago
7 0

Answer: Rapid Oxidation

Explanation:

In fireworks, the energy source is the rapid oxidation (burning or exploding) of gunpowder and other flammable chemicals. This burning causes the formation of gases that are heated and expand.

This rapid expansion involves three forms of energy : 1) The motive force to carry aerial fireworks into the sky, and to separate parts of them, 2) The heated molecules that give off radiance (visible light) in various forms of displays, and 3) The energetic vibration of air molecules that creates the sound of explosions.

Paladinen [302]4 years ago
6 0

chemical energy converts  into light, heat and sound  energy

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An car battery sends an electrical current one direction through a circuit in the car. Based on this, what type of current is a
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Answer:

A

Explanation:

the current passed in car is fixed and responsible for electric devices in car moves in one direction only but there are some cars has alternating cars to make induced current in its coils allowing it to move without fuel(as exception)

7 0
3 years ago
The force required to maintain an object at a constant speed in free space is equal to __________
rusak2 [61]
The correct answer is: zero.
8 0
3 years ago
A child holds onto a string attached to a toy boat and exerts a force of 7.5 N to pull the boat a distance of 9.2 m a long a str
soldi70 [24.7K]

The work that need to do is 66.24 J.

<h3>Explanation :</h3>

Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

\boxed {\bold {W = F \times s \times \cos(\theta)}}

If :

  • W = work (J)
  • F = force (N)
  • s = shift (m)
  • θ = elevation angle (°)

We know that :

  • x = the horizontal shift = 9,2 m
  • θ = elevation angle = 15°

W = work = ... J

W = F \times s \times \cos(\theta) \\ W = 7.5 \times 9.2 \times \cos(15) \\ W = 69 \times 0.96 = 66.24 \: J

So, the work that need to do is 66.24 J.

<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>

<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>

<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>

5 0
4 years ago
PLEASE HELP AS FAT WILL GIVE BRAILIEST TO MOST SPECIFIC AND CORRECT ANSWER
Bas_tet [7]

Answer:

Time

Explanation:

8 0
4 years ago
7. These temperatures were recorded in Pasadena for a week in April. 87 85 80 78 83 86 90 Find each of these. (a) Mean (e) Range
slega [8]

Answer:

a) Mean = 84.14

b) Median = 85

c) Mode = no mode (since there is no variable that appears more than once in this dataset)

d) Midrange = 84

e) Range = 12

f) Variance = 14.69

g) Standard deviation = 3.83

Explanation:

The raw data to be processed is

87 85 80 78 83 86 90

a) Mean = (Σx)/N

The mean is the sum of variables divided by the number of variables

x = each variable

N = number of variables = 7

Mean = (87+85+80+78+83+86+90)/7

Mean = 84.14

b) Median is the number in the middle of the dataset when the variables are arranged in ascending or descending order.

Arranging the data in ascending order

78, 80, 83, 85, 86, 87, 90

The number in the middle is the 4th number = 85

Median = 85

c) Mode is the variable that occurs the most in a distribution.

For this question, all of the variables occur only once, with no variable occurring more than once. Hence, there is no mode for this dataset.

d) Midrange is the arithmetic mean of the highest and lowest number in the dataset.

Mathematically,

Midrange = (Highest + Lowest)/2

Midrange = (90 + 78)/2

Midrange = 84

e) Range is the difference the highest and the lowest numbers in a dataset.

Range = 90 - 78 = 12

f) Variance is an average of the squared deviations from the mean.

Mathematically,

Variance = [Σ(x - xbar)²/N]

xbar = mean

Σ(x - xbar)² = (78 - 84.14)² + (80 - 84.14)² + (83 - 84.14)² + (85 - 84.14)² + (86 - 84.14)² + (87 - 84.14)² + (90 - 84.14)² = 102.8572

Variance = (102.8572)/7

Variance = 14.69

g) Standard deviation = √(variance)

Standard deviation = √(14.69)

Standard deviation = 3.83

Hope this Helps!!!

8 0
4 years ago
Read 2 more answers
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