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4 years ago

What type of energy conversion occurs at the moment fireworks explode?

Physics

2 answers:

allsm [11]4 years ago

7 0

Answer: Rapid Oxidation

Explanation:

In fireworks, the energy source is the rapid oxidation (burning or exploding) of gunpowder and other flammable chemicals. This burning causes the formation of gases that are heated and expand.

This rapid expansion involves three forms of energy : 1) The motive force to carry aerial fireworks into the sky, and to separate parts of them, 2) The heated molecules that give off radiance (visible light) in various forms of displays, and 3) The energetic vibration of air molecules that creates the sound of explosions.

Paladinen [302]4 years ago

6 0

chemical energy converts into light, heat and sound energy

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Does sunlight really take 8 minutes to reach your eyes?

Brums [2.3K]

It takes sunlight 8 minutes to reach earth , so yes

3 0

3 years ago

Read 2 more answers

Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m

Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

$m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s$

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

$V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}$

Substituting,

$V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}$

$V_{cm} = 1.034m/s$

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

$m_1v_1+m_2v_2 = (m_1+m_2)v_f$

Where here $v_f$ is the velocity after the collision.

$v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}$

$v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}$

$v_f = 1.034m/s$

8 0

4 years ago

The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental

pav-90 [236]

A) $5.0\cdot 10^{-11} m$

The energy of an x-ray photon used for single dental x-rays is

$E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J$

The energy of a photon is related to its wavelength by the equation

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34}Js$ is the Planck constant

$c=3\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

Re-arranging the equation for the wavelength, we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m$

B) $2.0\cdot 10^{-11} m$

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

$E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J$

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m$

4 0

3 years ago

Which statement describes an energy measurement?<br> apes

BARSIC [14]

Answer:

Many people are familiar with kilogram calories, which are often used to measure the energy available in food.

Explanation:

Quantities of energy given in one unit can always be converted to any other unit of energy. For example, 1 gram calorie is equivalent to 4.186 joules, which is used to measure heat energy.

5 0

3 years ago

If the resistance in a circult remains constant, what happens to the electric power when the current increases?

Ipatiy [6.2K]

b) the power will decrease

6 0

3 years ago