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NeTakaya
3 years ago
14

A 100-w light bulb is about 16% efficient. how many joules of heat energy are siddipated by the bulb each second

Chemistry
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

84 Joules are wasted per second.

Explanation:

An efficiency of 16% means 84% is wasted as heat energy.  

Therefore;

For a 100W bulb;

Heat wasted = 84/100 × 100 W

                      = 84 W

Therefore;

84 W or 84 joules are wasted as heat per second

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The representative particles of a covalent compound is called
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a molecule

Explanation:

 A molecule is the smallest unit quantity of a compound which can exist by itself and retain ALL the properties of the original substance.

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What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et
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The reaction of 1-bromo-2-methylpropane (isobutyl bromide), (CH_3)_2CHCH_2Br, with Mg, and Et_2O results in the formation of an adduct of formula (CH_3)_2CHCH_2MgBr known as grignard reagent, an organometallic reagent, which on reacting with H_3O^{+} results in the formation of isobutane.

The reaction is shown in the image.

4 0
3 years ago
Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer
Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is  K_c= 2.8*10^{-4}

Explanation:

      From  the question we are told that

              The chemical reaction equation is

      Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)}  -----> 2Fe_{(s)} + 3H_{2} O_{(g)}

The voume of the misture is  V_m = 5.4L  

  The molar mass of  Fe_{2} O_{3}_{(s)} is a constant with value of  M_{Fe_{2} O_{3}_{(s)} } = 160g/mol

    The molar mass of  H_{2}_{(g)}    is a constant with value of  H_2 = 2g/mol

   

    The molar mass of  H_{2}O    is a constant with value of  H_2O = 18g/mol

Generally the number of moles  is mathematically given as

                     No \ of \ moles \ = \frac{mass}{molar\  mass}

    For   Fe_{2} O_{3}_{(s)}

          No \ of\ moles = \frac{3.54}{160}

                                = 0.022125 \ mols

     For  H_{2}

               No \ of\ moles = \frac{3.63}{2}

                                = 1.815 \ mols

       For  H_{2}O

                         No \ of\ moles = \frac{2.13}{18}

                                              = 0.12 \ mols

Generally the concentration of a compound  is mathematicallyrepresented  as

       Concentration  = \frac{No \ of \ moles }{Volume }

      For   Fe_{2} O_{3}_{(s)}

                Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}

                                         = 4.10*10^{-3}M                          

       For  H_{2}

                  Concentration[H_2] = \frac{1.815}{5.4}

                                           = 0.336M

      For  H_{2}O

                Concentration [H_2O] = \frac{0.12}{5.4}

                                                  = 0.022M

  The equilibrium constant  is mathematically represented as

                K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}

  Considering H_2O  \ for \ product

            And      H_2  \ for  \ reactant

At  equilibrium the

                    K_c = \frac{0.022}{0.336}

                          K_c= 2.8*10^{-4}

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A balloon filled with helium occupies 21.0ft³ at 55.0°F. Find the temperature of the helium if the volume of the balloon decreas
harkovskaia [24]

Answer:

Assuming pressure is held constant,the question reduces to a ratio and proportion type of question where;

At constant pressure,

21.0ft³-55.0°F

11.0fy³=11.0ft³/21.0ft³×55°F

The temperature is 28.809°F≈29°F

6 0
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